sxhy @ 2023-11-13 11:10:16
#include<iostream>
using namespace std;
#include<iomanip>
#include<algorithm>
#include<string>
#include<math.h>
int main() {
std::ios::sync_with_stdio(false); std::cin.tie(0);
string s;
int n;
cin>>n>>s;
for(int i=0;i<s.length();i++)
{ if(s[i]+n>'z'){s[i]=((s[i]-'a'+1+n)%26-1+'a');cout << (char)s[i];}
else{cout <<(char) (s[i]+n);}
}
}
把-‘a’+1和-1+‘a’的1删掉就可以过,不然就错第三个点
by HearTheWindSing @ 2023-11-13 11:51:23
@sxhy 比如当s[i]='a',n=25时有1就会出问题
by sxhy @ 2023-11-13 11:58:05
@HearTheWindSing 感谢