xi_inluogu @ 2023-11-14 16:33:13
#include<stdio.h>
int main()
{
int n;
scanf("%d",&n);
int a[100];
for(int i = 0;i < n;i++)
{
int x;
scanf("%d",&x);
a[i] = x;
}
for(int i = 0;i < n;i++)
{
int x = a[i];
switch(x)
{
case 0:
printf("XXX");
break;
case 1:
printf("..X");
break;
case 2:
printf("XXX");
break;
case 3:
printf("XXX");
break;
case 4:
printf("X.X");
break;
case 5:
printf("XXX");
break;
case 6:
printf("XXX");
break;
case 7:
printf("XXX");
break;
case 8:
printf("XXX");
break;
case 9:
printf("XXX");
break;
}
if(i < n-1) printf(".");
}
printf("\n");
for(int i = 0;i < n;i++)
{
int x = a[i];
switch(x)
{
case 0:
printf("X.X");
break;
case 1:
printf("..X");
break;
case 2:
printf("..X");
break;
case 3:
printf("..X");
break;
case 4:
printf("X.X");
break;
case 5:
printf("X..");
break;
case 6:
printf("X..");
break;
case 7:
printf("..X");
break;
case 8:
printf("X.X");
break;
case 9:
printf("X.X");
break;
}
if(i < n-1) printf(".");
}
printf("\n");
for(int i = 0;i < n;i++)
{
int x = a[i];
switch(x)
{
case 0:
printf("X.X");
break;
case 1:
printf("..X");
break;
case 2:
printf("XXX");
break;
case 3:
printf("XXX");
break;
case 4:
printf("XXX");
break;
case 5:
printf("XXX");
break;
case 6:
printf("XXX");
break;
case 7:
printf("..X");
break;
case 8:
printf("XXX");
break;
case 9:
printf("XXX");
break;
}
if(i < n-1) printf(".");
}
printf("\n");
for(int i = 0;i < n;i++)
{
int x = a[i];
switch(x)
{
case 0:
printf("X.X");
break;
case 1:
printf("..X");
break;
case 2:
printf("X..");
break;
case 3:
printf("..X");
break;
case 4:
printf("..X");
break;
case 5:
printf("..X");
break;
case 6:
printf("X.X");
break;
case 7:
printf("..X");
break;
case 8:
printf("X.X");
break;
case 9:
printf("..X");
break;
}
if(i < n-1) printf(".");
}
printf("\n");
for(int i = 0;i < n;i++)
{
int x = a[i];
switch(x)
{
case 0:
printf("XXX");
break;
case 1:
printf("..X");
break;
case 2:
printf("XXX");
break;
case 3:
printf("XXX");
break;
case 4:
printf("..X");
break;
case 5:
printf("XXX");
break;
case 6:
printf("XXX");
break;
case 7:
printf("..X");
break;
case 8:
printf("XXX");
break;
case 9:
printf("XXX");
break;
}
if(i < n-1) printf(".");
}
printf("\n");
return 0;
}
思路是按照5行各个输出,按照样例检查了输出的应该没问题,但测试就全错。
by Missdie @ 2023-11-14 16:41:54
@xi_inluogu 你这个输不进去,把
scanf("%d",&x);
改成
scanf("%1d",&x);
by kevinchw @ 2023-11-14 16:43:36
长度为n,你为啥输了n个整数?
by xi_inluogu @ 2023-11-14 16:45:03
@Missdie 大佬为啥原来的输不进去改成这样就能输进去了啊
by xi_inluogu @ 2023-11-14 16:46:34
@kevinchw 这是输入一行数的意思吗?
by Missdie @ 2023-11-14 16:46:45
@xi_inluogu 蛤,因为%1d就是占位一位整数啊
by Missdie @ 2023-11-14 16:47:24
@xi_inluogu 当然也可以字符串读入
by xi_inluogu @ 2023-11-14 16:49:16
@Missdie 已经懂了,谢谢佬
by xi_inluogu @ 2023-11-14 16:49:47
@kevinchw 已经懂了,谢谢佬