lizhuorong @ 2023-11-18 16:54:24
60分的代码:
#include <cmath>
#include<bits/stdc++.h>
using namespace std;
int z[8];
bool f(int a,int b,int c)
{
z[0]=a/100;
z[1]=a/10%10;
z[2]=a%10;
z[3]=b/100;
z[4]=b/10%10;
z[5]=b%10;
z[6]=c/100;
z[7]=c/10%10;
z[8]=c%10;
if(z[0]+z[1]+z[2]+z[3]+z[4]+z[5]+z[6]+z[7]+z[8]!=45||z[0]*z[1]*z[2]*z[3]*z[4]*z[5]*z[6]*z[7]*z[8]!=362880){
return false;
}
return true;
}
int main(){
int a,b,c,k;
cin>>a>>b>>c;
int z;
int num=0;
int a1,a2,a3,a4,a5,a6,a7,a8,a9;
k=__gcd(__gcd(a,b),c);
a/=k;b/=k;c/=k;
for(int i=1;i<=999;i++){
int A=a*i,B=b*i,C=c*i;
if(f(A,B,C)){
num=1;
cout<<A<<" "<<B<<" "<<C<<endl;
}
}
if(num=0){
cout<<"No!!!";
}
}
by shiyueheng @ 2023-11-18 17:03:38
#include<bits/stdc++.h>
using namespace std;
int main()
{
int a,b,c,n[10],s=1,flag=1;
cin>>a>>b>>c;
for(int i=1;i<=333;i++)
{
int m[10]={0};
flag=1;
int d=a*i;
int e=b*i;
int f=c*i;
n[0]=d/100;
n[1]=d%100/10;
n[2]=d%10;
n[3]=e/100;
n[4]=e%100/10;
n[5]=e%10;
n[6]=f/100;
n[7]=f%100/10;
n[8]=f%10;
for(int j=0;j<9;j++)
{
for(int k=1;k<=9;k++)
{
if(n[j]==k)
{
m[k]++;
}
}
}
for(int j=1;j<=9;j++)
{
if(m[j]!=1)
{
flag=0;
}
}
if(flag==1)
{
cout<<d<<' '<<e<<' '<<f<<endl;
s=0;
}
}
if(s==1)
{
cout<<"No!!!";
}
return 0;
}
by lizhuorong @ 2023-11-18 17:04:43
@shiyueheng 谢谢
by shiyueheng @ 2023-11-18 17:05:12
100分代码