jcjkyx110507 @ 2023-11-24 20:56:43
#include<bits/stdc++.h>
using namespace std;
int main(){
unsigned long n,ans=0;
cin>>n;
for(int i=1;i<=n;i++){
long long f=1;
for(int j=1;j<=i;j++)
f*=j;
ans+=f;
}
cout<<ans<<endl;
return 0;
}by NO_OI_NO_LIFE @ 2023-11-24 21:12:57
@jinzhilong 你想学的高精度在这
by xiaoshumiao @ 2023-11-24 21:16:44
@jinzhilong 顺便说一句，这题高精乘可以用高精乘低精，别想复杂了。
by jcjkyx110507 @ 2023-11-24 21:29:12
@zyh0516_lucky @xiaoshumiao Thank you for your help!
by zhangshengzhe1 @ 2023-12-09 11:35:17
@jinzhilong 用高精度