在输出前加：
if(x%60>50){
printf("%d:%d",6-x/60,x%60-50);
return 0;
}
by qishifeng0001 @ 2023-11-26 20:45:35
还是 $0pts$
```cpp
#include<bits/stdc++.h>
using namespace std;
int main(){
double a,b;
cin>>a>>b;
//a/b↑
int x=ceil(a/b);
if(x%60>50){
printf("%d:%d",6-x/60,x%60-50);
return 0;
}
printf("%d:%d",7-x/60,50-x%60);
return 0;
}
```
by bcbgszyzh @ 2023-11-26 20:46:22
@[bcbgszyzh](/user/726902) 我没做这道题，但我觉得你些简单了哦。普及-的题不至于这么简单吧（除了P1372）
by penguin_is_cool @ 2023-11-27 15:43:01
是不是还要考虑两点：①题目中有要求输出格式为 HH:MM，分别代表该时间的时和分。必须输出两位，不足前面补 0。②万一是要前一天出发呢？
by outl @ 2023-11-28 08:23:58
@[outl](/user/599894)
wa 50pts:
```cpp
#include<bits/stdc++.h>
using namespace std;
int main(){
double a,b;
scanf("%lf%lf",&a,&b);
//a/b↑
int x=ceil(a/b);
if(x%60>50){
if(x%60-50<10){
printf("0%d:0%d",6-x/60,x%60-50);
return 0;
}
printf("0%d:%d",6-x/60,x%60-50);
return 0;
}
if((50-x%60)<10){
printf("0%d:0%d",7-x/60,50-x%60);
return 0;
}
printf("0%d:%d",7-x/60,50-x%60);
return 0;
}
```
by bcbgszyzh @ 2023-11-28 20:44:19
```cpp
#include<iostream>
using namespace std;
int main(){
int s,v,t,h,m;
cin>>s>>v;
t=s/v+10;
if(s%v!=0){
t++;
}
if(t<=8*60){
h=(8*60-t)/60;
m=(8*60-t)%60;
}else{
h=(24*60-(t-8*60))/60;
m=(24*60-(t-8*60))%60;
}
if(h<10){
cout<<0;
}
cout<<h<<':';
if(m<10){
cout<<0;
}
cout<<m;
return 0;
}
```
by outl @ 2023-11-28 22:50:13
@[bcbgszyzh](/user/726902) 缺少考虑万一晚上00:00之前就出发的情况
by outl @ 2023-11-28 22:51:44
@[bcbgszyzh](/user/726902)
```
#include<bits/stdc++.h>
#include<cstdio>
#include<cmath>
using namespace std;
int main()
{
int s,v;
scanf("%d%d",&s,&v);
int t_min = ceil(1.0 * s / v) + 10; //向上取整, 分钟为单位
int time_sum = 60 * (24 + 8); //时间限制
int ans = time_sum - t_min;//从0点算，何时出发
int h = (ans / 60) % 24;
int min = ans % 60;
printf("%02d:%02d",h,min);
return 0;
}
```
by Dark_Monarch @ 2023-12-03 15:25:50
@[ywz121014](/user/1032282) ac 程序？
by bcbgszyzh @ 2023-12-03 16:41:21
@[bcbgszyzh](/user/726902) 发了
by Dark_Monarch @ 2023-12-04 19:02:11