tlbcsky @ 2023-12-22 22:24:28

#include<bits/stdc++.h>
using namespace std;
int main()
{
    int n;
    cin>>n;
    string s;
    cin>>s;
    for(int i=0;i<s.size();i++)
    {
        cout<<char(s[i]+n);
    }
    return 0;
}

by xiao_dong_xi @ 2023-12-22 22:27:11

少了特判。想一想，如果输入有 z 怎么办？

by xiao_dong_xi @ 2023-12-22 22:27:58

@tlbcsky

by tlbcsky @ 2023-12-22 22:28:45

@JoneSno 噢噢噢噢懂了

by tlbcsky @ 2023-12-22 22:39:06

@JoneSno ```

include<bits/stdc++.h>

using namespace std; int main() { int n; cin>>n; string s; cin>>s; for(int i=0;i<s.size();i++) { if(s[i]=='z') { cout<<char(s[i]-26+n); } else cout<<char(s[i]+n); } return 0; }

这下好了只有四十分了

by xiao_dong_xi @ 2023-12-22 22:40:39

不是啊，不仅仅是 z，还有其他可能。比如 n=27,s[i]=a

by xiao_dong_xi @ 2023-12-22 22:43:38

@tlbcsky

#include<bits/stdc++.h>
using namespace std;
int main()
{
    int n;
    cin>>n;
    string s;
    cin>>s;
    for(int i=0;i<s.size();i++)
    {
        s[i]=(s[i]+n-'a')%26+'a';
        cout<<s[i];
    }
    return 0;
}

可以看懂吗？

by tlbcsky @ 2023-12-23 15:22:04

@JoneSno 勉强吧，不是特别能看懂

by xiao_dong_xi @ 2023-12-23 15:53:26

或者你可以这样

#include<bits/stdc++.h>
using namespace std;
int main()
{
    int n;
    cin>>n;
    string s;
    cin>>s;
    for(int i=0;i<s.size();i++)
    {
        for(int j=1;j<=n;j++)//循环n次，每次右移一位，并判断是否大于z。
        {
            s[i]+=1;
            if(s[i]>'z')s[i]='a';
        } 
        //s[i]=(s[i]+n-'a')%26+'a';
        cout<<s[i];
    }
    return 0;
}

by xiao_dong_xi @ 2023-12-23 15:53:35

@tlbcsky

by tlbcsky @ 2023-12-23 18:53:32

@JoneSno 抱歉啊才看到