0分求佬看看

pdxdsbzl @ 2023-12-24 21:49:55

#include<stdio.h>
int main()
{
    int n,k;
    scanf("%d%d",&n,&k);
    double sum1,sum2;
    double p1=0;
    double p2=0;
    for(int i=1;i<=n;i++)
    {
        if(i%k==0)
        {
            sum2+=i;
            p2++;
            continue;
        }
        p1++;
        sum1+=i;
    }
    printf("%.1f ",sum2/p2);
    printf("%.1f",sum1/p1);
    return 0;
}

by HHYQ_07 @ 2023-12-24 22:12:26

@pdxdsbzl 用整型定义，最后运算平均数时乘上 1.0 结果就会自动变成浮点型的

#include<stdio.h>
int main()
{
    int n,k;
    scanf("%d%d",&n,&k);
    int sum1,sum2;
    int p1=0;
    int p2=0;
    for(int i=1;i<=n;i++)
    {
        if(i%k==0)
        {
            sum2+=i;
            p2++;
            continue;
        }
        p1++;
        sum1+=i;
    }
    printf("%.1f ",1.0*sum2/p2);
    printf("%.1f",1.0*sum1/p1);
    return 0;
}

求关

by pdxdsbzl @ 2023-12-25 09:04:58

@Voluminousness 关注啦，虽然但是，用这个好像也是WA，，甚至连样例都没过哦

by asdjklqwe123 @ 2023-12-25 10:43:16

把p1和p2变成int型就好了

by pdxdsbzl @ 2023-12-25 10:44:31

@asdjklqwe123 佬佬佬orz解决了！！！

by HHYQ_07 @ 2023-12-25 22:17:48

@pdxdsbzl 抱歉拿C++交的，C的话删去 return 0 就行了

by llhhss @ 2024-09-05 21:29:57

@pdxdsbzl

int main()
{
    int n,k;
    scanf("%d%d",&n,&k);
    double sum1,sum2;
    double p1=0;
    double p2=0;
    for(int i=1;i<=n;i++)
    {
        if(i%k==0)
        {
            sum2+=i;
            p2++;
            continue;
        }
        p1++;
        sum1+=i;
    }
    printf("%.1f ",sum2/p2);
    cout<<" ";
    printf("%.1f",sum1/p1);
    return 0;
}```