好像是计算出错，但没看出来

codecolorThD @ 2024-01-22 21:41:26

#include <iostream>
#include <string>
using namespace std;

int main() {
    string str;
    int all = 0,j = 0;
    cin >> str;
    for (int i = 0; i <= 11; i++) {
        if (str[i] != '-') {
            j++;
            all += int(str[i] - '0') * j;
        }
    }
    all %= 11;
    if (all == (str[12] - '0')||(all == 10 && str[12] == 'X'))
        cout << "Right";
    else if( all == 10)
        cout << str << '\b' << 'X';
    else
        cout << str << '\b' << all;
    return 0;
}

by FarmerDrone @ 2024-01-22 22:01:07

'\b'这种偷鸡的写法是不行的 这样就行了

#include <iostream>
#include <string>
using namespace std;

int main() {
    string str;
    int all = 0,j = 0;
    cin >> str;
    for (int i = 0; i <= 11; i++) {
        if (str[i] != '-') {
            j++;
            all += int(str[i] - '0') * j;
        }
    }
    all %= 11;
    if (all == (str[12] - '0')||(all == 10 && str[12] == 'X'))
        cout << "Right";
    else if( all == 10)
    {
        for (int i = 0; i <= 11; i++)
            cout << str[i];
        cout << "X" << endl; 
    }
    else
    {
        for (int i = 0; i <= 11; i++)
            cout << str[i];
        cout << all << endl; 
    }
    return 0;
}

by codecolorThD @ 2024-01-23 21:39:13

@xuyao35 谢谢，解决了。看来对于洛谷的机制还是得好好研究一下。