a___ @ 2017-01-22 14:07:20
#include<cstdio>
using namespace std;
int main()
{
int n;
char a[999999];
scanf ("%d%s",&n,a);
for (int i=0;a[i]!='\0';i++)
{
a[i]+=n%26;
putchar (a[i]);
}
return 0;
}
by svc330 @ 2017-01-22 14:43:30
'z'+1%26=??
by a___ @ 2017-01-22 15:17:23
哦,谢谢