AC_kkk0926 @ 2024-01-28 11:30:03
#include <bits/stdc++.h>
using namespace std;
int ac(int x){
if(x==1){
return 1;
}
else if(x==2){
return 2;
}
else{
return ac(x-1)+ac(x-2);
}
}
int main(){
int a;
cin>>a;
cout<<ac(a);
return 0;
}
by _QyGyQ_ @ 2024-01-28 11:31:20
这肯定炸,建议记忆化或者直接for递推
by _QyGyQ_ @ 2024-01-28 11:31:31
@AC_kkk0926
by AC_kkk0926 @ 2024-01-28 11:32:51
@meng_cen 额(⊙﹏⊙)不懂......
by _QyGyQ_ @ 2024-01-28 11:39:05
@AC_kkk0926
#include <bits/stdc++.h>
using namespace std;
const int N=1e6+7;
int v[N];
int main(){
v[1]=1;
v[2]=2;
int n;
cin>>n;
for(int i=3;i<=n;i++){
v[i]=v[i-1]+v[i-2];
}
cout<<v[n];
return 0;
}
这是大概思路,不过只有50分,100分要高精度
by AC_kkk0926 @ 2024-01-28 11:45:33
@meng_cen 我不会高精度
by _QyGyQ_ @ 2024-01-28 12:00:50
啊,这
by _QyGyQ_ @ 2024-01-28 12:02:00
@AC_kkk0926 建议去学一下P1601,题解会说明原理
by AC_kkk0926 @ 2024-01-28 18:50:13
@meng_cen ok