输入有问题！帮忙看一下（悬赏关注）

Algorithm_ZRF @ 2024-02-01 14:19:59

inline void Read() {
    cin >> n;
    for(int i = 1; i <= n; ++i) {
        for(int j = 1; j <= n; ++j) {
            cin >> mp[i][j];
        }
    }
    cin >> Start.x >> Start.y >> End.x >> End.y;
}

by Algorithm_ZRF @ 2024-02-01 14:24:30

附上变量定义：

int dx[] = {1,-1,0,0},
    dy[] = {0,0,1,-1};

struct co {
    int x,y;
};

struct ss {
    int x,y,dis;
};
int n;
co Start,End;
int mp[maxn][maxn];

by ___nyLittleT___ @ 2024-02-01 14:33:39

中间没有空格，你需要通过字符串读入再转为整数。 @Algorithm_ZRF

by Algorithm_ZRF @ 2024-02-01 14:36:01

@nyLittleT ？

by Algorithm_ZRF @ 2024-02-01 14:47:18

@nyLittleT char数组可以吗

by ___nyLittleT___ @ 2024-02-01 14:48:08

@Algorithm_ZRF 可以的

by Algorithm_ZRF @ 2024-02-01 14:50:25

@nyLittleT 谢谢

by ___nyLittleT___ @ 2024-02-01 14:50:28

@Algorithm_ZRF

char s[N];
for(int i=1;i<=n;i++){
  scanf("%s",s+1);//下标从1开始好处理一些
  for(int j=1;j<=n;j++) mp[i][j]=s[j]-'0';//转为整数
}

by Tsuri @ 2024-03-02 10:55:02

可以直接输入整数 scanf("%1d",&g[i][j]); 就可以了，每次只读一个

by Tiks_code @ 2024-03-17 10:51:47

int main() {
    cin >> n;
    for (int i = 1; i <= n; i++) {
            int x;
            cin >> x;
            sub(x,i);
    }
    cin >> st.first >> st.second >> ed.first >> ed.second;
    cout << bfs(st.first, st.second, 0) << endl;
}
void sub(int x,int i) {
    while (x) {
        for (int j = 1; j <= n; j++) {
            string str = to_string(x);
            str.reserve();
            int temp = stoi(str);
            a[i][j] = temp % 10;
            temp /= 10;

by Tiks_code @ 2024-03-17 10:52:41

@Tiks_code temp/=10下面再写一个x/=10