SbasdianJulian @ 2018-10-28 19:19:05
#include<bits/stdc++.h>
using namespace std;
int n;
string a;
int main(){
cin>>n;
cin>>a;
for(int i=0;i<a.length();i++){
a[i]+=n;
if(a[i]+n>'z'&&n<=26)a[i]-=26;
if(n>26)a[i]=(a[i]-'a'+n)%26+'a';
}
cout<<a;
return 0;
}
by LokiASG @ 2018-10-28 19:26:38
直接让它每次加的小于26即可
for(int i=0;i<a.length();i++){
a[i]+=n%26;
if(a[i]>'z')a[i]-=26;
}
by Jerrylee @ 2018-10-29 21:12:12
#include <bits/stdc++.h>
using namespace std;
int main()
{
string a;
int n,s,x;
cin>>n;
cin>>a;
s=a.size();
for(int i=0;i<=s-1;i++)
{
x=a[i]-'a';
x=(x+n)%26;
a[i]=x+'a';
cout<<a[i];
}
return 0;
}