m3o7o2n1 @ 2024-02-06 19:16:15
#include <stdio.h>
int main() {
int y,sum,n;
scanf("%d",&n);
while(n!=0){
y=n%10;
sum=sum*10+y;
n=n/10;
}
printf("%d",sum);
return 0;
}
by DFs_YYDS @ 2024-02-06 19:29:32
@m3o7o2n1 把
by DFs_YYDS @ 2024-02-06 19:30:53
@m3o7o2n1 试过了,可以AC
by Axolotl_awa @ 2024-02-06 19:33:04
@m3o7o2n1 你
sum
没初始化成0
by Axolotl_awa @ 2024-02-06 19:34:58
有的编译器会帮你把没初始化的初始化成0,但洛谷会给它一个随机值,
by Axolotl_awa @ 2024-02-06 19:36:20
还有你这题也太像题解了吧。。。
by m3o7o2n1 @ 2024-02-06 19:43:01
@DFs_YYDS 好的好的,太感谢了!!!/(ㄒoㄒ)/~~
by m3o7o2n1 @ 2024-02-06 19:43:56
@wuboyan714 好的好的明白了,太感谢了!!!இ௰இ
by m3o7o2n1 @ 2024-02-06 19:45:27
@wuboyan714 之前做过类似的数字反转题目,当时不会做就看题解记住了这种算法இ௰இ
by DFs_YYDS @ 2024-02-11 11:21:56
@m3o7o2n1 今天突然看到这个帖子,告诉你一个事情,你用0分的代码,把O2关了就能AC
by lunxiaotong0118 @ 2024-02-18 14:46:02
#include<bits/stdc++.h>
using namespace std;
int n,s=0;
int main()
{
cin>>n;
while(n) s=s*10+n%10,n/=10;
cout<<s;
return 0;
}