OIer_fish @ 2024-02-21 10:00:10
```
#include<bits/stdc++.h>
using namespace std;
int main(){
char str[20];
int cnt=0,ans=0;
scanf("%s",str+1);
int len=strlen(str+1);
for(int i=1;i<=len-1;i++){
if(str[i]=='-'){
continue;
}
int now=str[i]-'0';
cnt=cnt+1;
ans+=now*cnt;
}
ans=ans%11;
if(ans=10){
if(str[len]=='X'){
cout<<"Right"<<endl;
}
else{
str[len]='X';
printf("%s\n",str+1);
}
}
else{
if(str[len]=='0'+ans){
cout<<"Right"<<endl;
}
else{
str[len]='0'+ans;
printf("%s\n",str+1);
}
}
return 0;
}
```by Loyal_Soldier @ 2024-02-21 10:16:17
@YZHcsp AC代码：
#include<bits/stdc++.h>
using namespace std;
int main() {
int a,b,c,b1,b2,b3,c1,c2,c3,c4,c5,y;
char s;
scanf("%d-%d-%d-%c",&a,&b,&c,&s);
b1=b/100;
b2=b/10%10;
b3=b%10;
c1=c/10000;
c2=c/1000%10;
c3=c/100%10;
c4=c/10%10;
c5=c%10;
y=(a*1+b1*2+b2*3+b3*4+c1*5+c2*6+c3*7+c4*8+c5*9)%11;
if(s=='X'){
if(y==10){
cout<<"Right";
}
else{
printf("%d-%d-%d-%d",a,b,c,y);
}
}
else{
s=s-48;
if(y==10){
printf("%d-%d-%d-X",a,b,c);
}
else if(y==s){
cout<<"Right";
}
else{
printf("%d-%d-%d-%d",a,b,c,y);
}
}
return 0;
}by Loyal_Soldier @ 2024-02-21 10:17:45
一个很简单的题，不用数组就行
by OIer_fish @ 2024-02-21 10:23:51
@huangkaikai ...... 好吧 栓q
by xzy_caiji @ 2024-02-21 10:27:33
@YZHcsp 不要听楼上的！您的几乎是对的！只要把第17行的=改成==就行了！
by xzy_caiji @ 2024-02-21 10:28:23
就是把ans=10改成ans==10
by OIer_fish @ 2024-02-21 10:29:01
@xzy_caiji 为啥嘞 蒟蒻不理解
by xzy_caiji @ 2024-02-21 10:30:31
ans=10就是把ans赋值为10并返回10，而ans==10是判断ans是否等于10
by xzy_caiji @ 2024-02-21 10:32:03
if(ans=10){
……
}程序会一直进入这个分支，不管ans等不等于10
by xzy_caiji @ 2024-02-21 10:32:15
@YZHcsp
by xiangzhenze611 @ 2024-02-21 10:33:02
@YZHcsp 楼上说的没错，要判断两个值是否相等要用 ==