```
#include <iostream>
#include<cmath>
using namespace std;
double a[100][100];
int b[100][100];
int main()
{
int n, m;
cin >> n >> m;
for (int i = 0; i < n; i++)
{
for (int j = 0; j < m; j++) {
cin >> a[i][j];
b[i][j] = a[i][j];
}
}
for (int i = 1; i < (n - 1); i++)
{
for (int j = 1; j < (m - 1); j++) b[i][j] = round((a[i][j]+ a[i - 1][j] + a[i][j - 1] + a[i][j + 1] + a[i + 1][j]) / 5);
}
for (int i = 0; i < n; i++)
{
for (int j = 0; j < m; j++) cout << b[i][j]<<" ";
cout << endl;
}
return 0;
}
```
by jiejieya @ 2024-02-21 20:18:19
@[SHHD](/user/1236137) 是其上下左右及其原点灰度值的平均，所以
```cpp
a[i][j]=(a[i-1][j]+a[i][j-1]+a[i][j+1]+a[i+1][j])/4;
```
改成
```cpp
a[i][j]=(a[i-1][j]+a[i][j-1]+a[i][j+1]+a[i+1][j]+a[i][j])/5;
```
by xiangzhenze611 @ 2024-02-21 20:19:05
@[SHHD](/user/1236137) 另外，由于要取整，还要加个 `round` 函数
by xiangzhenze611 @ 2024-02-21 20:23:09
几个错的地方
1.
```
for (int i=1;i<(n-1);i++)
{
for (int j=1;j<(m-1);j++) a[i][j]=(a[i-1][j]+a[i][j-1]+a[i][j+1]+a[i+1][j])/4;
}
```
这边a[i][j]应该是其自己本身加邻边的数值的和再除5
2.还是同一位置比如一行a[i][1]你先修改了他的值，在接下来计算a[i][2]的值会受到影响，所以不如从新开一个数组来记录模糊过后的数值，这样就不会因为前面的修改而影响后面的值
3.题目要求取最近的整数，原本int类型无法做到，所以改用double类型，再用round（）函数进行四舍五入的操作
by jiejieya @ 2024-02-21 20:23:26
还有输出要空格！！！
by jiejieya @ 2024-02-21 20:25:24
@[xiangzhenze611](/user/1005749) 谢谢啦
by SHHD @ 2024-02-21 20:28:01
@[SHHD](/user/1236137) 不用谢
by xiangzhenze611 @ 2024-02-21 20:32:02
```cpp
//
#include <bits/stdc++.h>
using namespace std;
int a[100][100],b[100][100];
int main()
{
int n,m;
cin>>n>>m;
for (int i=0;i<n;i++)
{
for (int j=0;i<m;j++) cin>>a[i][j];
}
for (int i=1;i<(n-1);i++)
{
for (int j=1;j<(m-1);j++) round(b[i][j]=(a[i-1][j]+a[i][j-1]+a[i][j+1]+a[i+1][j]+a[i][j])/5);
}
for (int i=0;i<n;i++)
{
for (int j=0;j<m;j++) cout<<b[i][j]<<" ";
cout<<endl;
}
return 0;
}
```
超时了
by SHHD @ 2024-02-21 20:33:09
@[xiangzhenze611](/user/1005749) 再帮我看一下呗
by SHHD @ 2024-02-21 20:36:56
@[SHHD](/user/1236137) `round` 函数要用 `double`
by xiangzhenze611 @ 2024-02-21 20:46:01