qqjddw @ 2024-03-04 18:28:48
93分,14wa,有无大佬帮忙看一下。
#include <iostream>
#include <algorithm>
#include <cstring>
#include <queue>
using namespace std;
typedef pair<int, int> PII;
const int N = 310;
struct Node
{
int x, y, t;
};
int m, res;
int t[N][N];
bool st[N][N];
int dx[5] = {0, -1, 1, 0, 0}, dy[5] = {0, 0, 0, -1, 1};
int bfs()
{
queue<Node> q;
st[0][0] = true;
q.push({0, 0, 0});
while(q.size())
{
auto tt = q.front();
q.pop();
int x = tt.x, y = tt.y, res = tt.t;
if(t[x][y] == 1e9) return res;
for(int i = 0; i < 5; i++)
{
int nx = x + dx[i], ny = y + dy[i];
if(nx >= 0 && nx <= 300 && ny >= 0 && ny <= 300 && res + 1 < t[nx][ny] && !st[nx][ny])
{
st[nx][ny] = true;
q.push({nx, ny, res + 1});
}
}
}
return -1;
}
int main()
{
memset(t, 0x3f, sizeof t);
scanf("%d", &m);
for(int i = 1; i <= m; i++)
{
int mx, my, mt;
scanf("%d%d%d", &mx, &my, &mt);
t[mx][my] = min(t[mx][my], mt);
if(mx - 1 >= 0) t[mx - 1][my] = min(t[mx - 1][my], mt);
t[mx + 1][my] = min(t[mx + 1][my], mt);
if(my - 1 >= 0) t[mx][my - 1] = min(t[mx][my - 1], mt);
t[mx][my + 1] = min(t[mx][my + 1], mt);
}
cout << bfs() << endl;
return 0;
}
by qqjddw @ 2024-03-04 18:30:16
已经自行解决nx,ny无需判断,感谢各位
by aguang666 @ 2024-03-21 22:00:11
@qqjddw 大佬问题是啥呢,我看不出来
by qqjddw @ 2024-03-22 15:57:06
@aguang666 时间太久有点忘了,貌似是不要加nx<=30 && ny <= 300,因为这个人可以跑到横纵坐标300以外的点
by uniquealuo @ 2024-03-23 15:55:22
@qqjddw 哈哈哈,我也是14wa,没想到他可以跑到外面,感谢大佬orz
by aguang666 @ 2024-03-24 09:09:41
@qqjddw 是的,感谢大佬