#9过不了，help！！！

228527hu @ 2024-03-10 22:10:02

#include<stdio.h>
int main(){
    int s,v;
    scanf("%d %d",&s,&v);
    int hour,minute;
    hour=(s/v)/60;
    if((s/v)%60==0)
        minute=(s/v)%60;
    else{
        minute=(s/v)%60+1;
    }
    if(hour>=24)
        return 0;
    if(minute>50){
        if(hour<=6){
            printf("0%d:%d",6-hour,110-minute);
        }
        else if((30-hour)<10){
            printf("0%d:%d",30-hour,110-minute);
        }
        else{
            printf("%d:%d",30-hour,110-minute);
        }
    }
    else{
        if(minute<=40){
            if(hour<=7){
                printf("0%d:%d",7-hour,50-minute);
            }
            else if((31-hour)<10){
                printf("0%d:%d",31-hour,50-minute);
            }
            else{
                printf("%d:%d",31-hour,50-minute);
            }
        }
        else{
            if(hour<=7){
                printf("0%d:0%d",7-hour,50-minute);
            }
            else if((31-hour)<10){
                printf("0%d:0%d",31-hour,50-minute);
            }
            else{
                printf("%d:0%d",31-hour,50-minute);
            }
        }
    }
    return 0;
      }

by plokmnjiu @ 2024-03-10 22:52:48

#include<stdio.h>
int main(){
    int s,v;
    scanf("%d %d",&s,&v);
    int hour,minute;
    hour=(s/v)/60;
    if((s/v)%60==0)  // 建议用三目运算符，这样写太麻烦了
        minute=(s/v)%60;
    else{  // 奇怪的花括号，上面没有但是这里有
        minute=(s/v)%60+1;
    }
    if(hour>=24)  // 这完全没必要，难道是为了安全感么
        return 0;
    if(minute>50){  // 没有必要分情况这么细
        // 这里太繁杂了，为什么一定要用printf？
        // hour的正负问题完全可以这么写
        /*
        hour=6-hour,minute=110-minute;
        if(hour<0)hour+=24;
        if(hour<10)cout<<'0'；
        cout<<hour<<':'minute<<'\n';
        */
        if(hour<=6){
            printf("0%d:%d",6-hour,110-minute);
        }
        else if((30-hour)<10){
            printf("0%d:%d",30-hour,110-minute);
        }
        else{
            printf("%d:%d",30-hour,110-minute);
        }
    }
    else{
        // 重复的东西太多，把状态合并一些，下面完全是复制粘贴
        // 先进行计算，负数就再加上一轮，有前导零就先输出
        // 没有必要在计算之前就想好所有情况
        if(minute<=40){
            if(hour<=7){
                printf("0%d:%d",7-hour,50-minute);
            }
            else if((31-hour)<10){
                printf("0%d:%d",31-hour,50-minute);
            }
            else{
                printf("%d:%d",31-hour,50-minute);
            }
        }
        else{
            if(hour<=7){
                printf("0%d:0%d",7-hour,50-minute);
            }
            else if((31-hour)<10){
                printf("0%d:0%d",31-hour,50-minute);
            }
            else{
                printf("%d:0%d",31-hour,50-minute);
            }
        }
    }
    return 0;
}

by plokmnjiu @ 2024-03-10 22:55:18

虽然是橙题，但是写出了蓝题的气势