sscyy @ 2024-03-18 20:30:55
a,b=map(int,input().split())
def is_prime(num):
if num<2:
return False
for i in range(2,int(num**0.5)+1):
if num%i==0:
return False
return True
def huiwen(num):
return str(num)==str(num)[::-1]
for i in range(a,b+1):
if is_prime(i) and huiwen(i):
print(i)
by NC20061226 @ 2024-03-18 20:34:26
嗯,这题应该不能用 Python 吧?(C艹都有可能超时。
by yanghb666 @ 2024-03-23 15:56:58
看看AC代码:
from math import *
z=[5,7,11]
x=[int(i) for i in input().split()]
for i in range(1,10,2):
for j in range(0,10):
for k in range(0,10):
a=i*10000+j*1000+k*100+j*10+i
for m in range(3,round(sqrt(a) + 1)):
if a % m==0:
break
else:
z.append(a)
for i in range(1,10,2):
for j in range(0,10):
a=i*100+j*10+i
for k in range(3,round(sqrt(a) + 1)):
if a%k==0:
break
else:
z.append(a)
for i in range(1,10,2):
for j in range(0,10):
for k in range(0,10):
for l in range(0,10):
a=1000000*i+j*100000+k*10000+l*1000+k*100+j*10+i
for m in range(3,round(sqrt(a) + 1)):
if a % m == 0:
break
else:
z.append(a)
z.sort()
for i in z:
if x[0]<=i<=x[1]:
print(i)