CEFqwq @ 2024-03-23 15:34:20
upd 没写 pup 10 分,写了变 0 分/jk
#include<bits/stdc++.h>
#define int long long
using namespace std;
#define mxn 200005
struct node{
int l, r, vl, lzy;
}tr[mxn << 2 | 3];
int a[mxn], n, q;
int ls(int u){
return (u << 1);
}
int rs(int u){
return (u << 1 | 1);
}
void glz(int u, int k){
tr[u].lzy += k;
}
void gv(int u, int k){
tr[u].vl += k;
}
int md(int l, int r){
return (l + r) >> 1;
}
void pup(int u){
tr[u].vl = tr[ls(u)].vl + tr[rs(u)].vl;
}
void build(int u, int l, int r){
tr[u].l = l;
tr[u].r = r;
if (l == r){
tr[u].vl = a[l];
return;
}
int mid = md(l, r);
build(ls(u), l, mid);
build(rs(u), mid + 1, r);
pup(u);
}
bool inr(int l, int r, int ql, int qr){
return (ql <= l && qr >= r);
}
bool otr(int l, int r, int ql, int qr){
return (ql > r || qr < l);
}
void pdn(int u, int l, int r){
int mid = md(l, r);
glz(ls(u), tr[u].lzy);
gv(ls(u), tr[u].lzy * (mid - l + 1));
glz(rs(u), tr[u].lzy);
gv(rs(u), tr[u].lzy * (r - (mid + 1) + 1));
tr[u].lzy = 0;
}
void upd(int u, int ql, int qr, int x){
// cout << u << " " << tr[u].l << " " << tr[u].r << " " << tr[u].vl << " " << ql << " " << qr << " " << x << "\n";
if (inr(tr[u].l, tr[u].r, ql, qr)){
glz(u, x);
gv(u, x * (tr[u].r - tr[u].l + 1));
// cout << u << " " << tr[u].l << " " << tr[u].r << " " << tr[u].vl << " " << ql << " " << qr << " " << x << "\n";
return;
}
// cout << u << " " << tr[u].l << " " << tr[u].r << " " << tr[u].vl << " " << ql << " " << qr << " " << x << "\n";
if (otr(tr[u].l, tr[u].r, ql, qr))
return;
pdn(u, ql, qr);
// int mid = md(tr[u].l, tr[u].r);
upd(ls(u), ql, qr, x);
upd(rs(u), ql, qr, x);
pup(u);
}
int qry(int u, int ql, int qr){
int res = 0;
if (inr(tr[u].l, tr[u].r, ql, qr))
return tr[u].vl;
if (otr(tr[u].l, tr[u].r, ql, qr))
return 0;
pdn(u, ql, qr);
// int mid = md(tr[u].l, tr[u].r);
res += (qry(ls(u), ql, qr) + qry(rs(u), ql, qr));;
return res;
}
signed main(){
ios::sync_with_stdio(false);
cin.tie(0);cout.tie(0);
cin >> n >> q;
for (int i = 1; i <= n; i++)
cin >> a[i];
build(1, 1, n);
while (q--){
int op;
cin >> op;
if (op == 1){
int l, r, x;
cin >> l >> r >> x;
upd(1, l, r, x);
}else{
int l, r;
cin >> l >> r;
cout << qry(1, l, r) << "\n";
}
// for (int i = 1; i <= n; i++)
// cout << qry(1, i, i) << " ";
// cout << "\n";
}
}
by Terrible @ 2024-03-23 16:42:05
@爱肝大模拟的tlxjy
pdn(u, tr[u].l, tr[u].r);
将你上面贴的代码改过就 AC 了