求助

MaxLKY @ 2024-03-24 10:05:10

#include<bits/stdc++.h>
using namespace std;
int main(){
    strin a="",b;
    while(cin>>b){
        a=a+b;
    }
    int cnt=0;
    cout<<sqrt(a.size())<<" ";
    /*for(int i=1;i<=a.size();i++){
        if(a[i]=='0'){
            cnt++;
        }else{
            cout<<cnt<<" ";
            cnt=0;
        }
    }*/
    return 0;
}

by chenbingjie @ 2024-03-30 11:43:15

@MaxLKY cnt=1;

by canwen @ 2024-04-05 15:16:19

我写的AC了嘻嘻 我的思路先读取一行代码 统计n，然后循环读取，模拟即可

#include<iostream>
#include<cstring>
using namespace std;
char shuzu[200];int ans[201*201];
int main(){
    int flag=0;//flag=0，统计0；等于1，统计1 
    cin>>shuzu;int num=0,j=0;
    int n=strlen(shuzu);
    for(int i=0;i<n;i++){
        if(flag==0) {
            if(shuzu[i]=='0') {
                num++;
            }else{
                ans[++j]=num;
                //cout<<flag<<"的统计截止："<<ans[j]<<endl;
                num=1;
                flag=1;
            }
        }else{
            if(flag==1){
                if(shuzu[i]=='1') {
                num++;
            }else{
                ans[++j]=num;
                //cout<<flag<<"的统计截止："<<ans[j]<<endl;
                num=1;
                flag=0;
            }
            }
        }

    }

    for(int i=2;i<=n;i++){
    cin>>shuzu;
    for(int i=0;i<n;i++){
        if(flag==0) {
            if(shuzu[i]=='0') {
                num++;
            }else{
                ans[++j]=num;
                //cout<<flag<<"的统计截止："<<ans[j]<<endl;
                num=1;
                flag=1;
            }
        }else{
            if(flag==1){
                if(shuzu[i]=='1') {
                num++;
            }else{
                ans[++j]=num;
                //cout<<flag<<"的统计截止："<<ans[j]<<endl;
                num=1;
                flag=0;
            }
            }
        }

    }
    }
    cout<<n<<" ";
    for(int i=1;i<=j;i++){
        cout<<ans[i]<<" ";
    }
    cout<<num;

}

by MaxLKY @ 2024-04-26 22:40:42

栓Q啊