Python写的代码，才40分，题目看得不是太懂

P1603 斯诺登的密码

tang_123458 @ 2024-03-27 19:29:31

这个题不是看得太懂，用Python写的代码，不知道哪里出问题了。输入样例：You are a three eight pig .，我得到的结果是1964，而标准答案是10964.不知道为甚么是10.1的平方不是1吗？

#斯诺登密码
s1 = "one two three four five six seven eight nine ten eleven twelve"
s2 = " thirteen fourteen fifteen sixteen seventeen eighteen nineteen twenty"
s3 = " a both another first second third"
s =s1 + s2 + s3
lst = s.split()
nums = [i for i in range(1,21)]
n = [1,2,1,1,2,3]
nums.extend(n)
#print(nums)

dct = {}
for key,val in zip(lst,nums):
    dct[key] = val

#print(dct.keys())
mima = []
str1 = input().split()
for word in str1:
    if word in dct.keys():
        a = dct[word] ** 2 % 100
        if a != 0:
               mima.append(a)

if len(mima):
    mima.sort()
    mima = [str(i) for i in mima]
    print(''.join(mima))
else:
    print(0)

by tang_123458 @ 2024-03-28 08:44:45

过了,认真读题，认真读题

#斯诺登密码
s1 = "one two three four five six seven eight nine ten eleven twelve"
s2 = " thirteen fourteen fifteen sixteen seventeen eighteen nineteen twenty"
s3 = " a both another first second third"
s =s1 + s2 + s3
lst = s.split()
nums = [i for i in range(1,21)]
n = [1,2,1,1,2,3]
nums.extend(n)
#print(nums)

dct = {}
for key,val in zip(lst,nums):
    dct[key] = val

#print(dct.keys())
mima = []
str1 = input().split()
for word in str1:
    if word in dct.keys():
        a = dct[word] ** 2 % 100
        if a != 0:
            mima.append(a)

if len(mima):
    mima.sort()
    for i in range(len(mima)):
        if i != 0 and mima[i] < 10:
            mima[i] = '0'+str(mima[i])
        else:
            mima[i] = str(mima[i])
    print(''.join(mima))
else:
    print(0)
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