欧拉路径61分求条(悬一关)

P2731 [USACO3.3] 骑马修栅栏 Riding the Fences

danlao @ 2024-04-30 17:49:53

记录

code

#include <bits/stdc++.h>
using namespace std;
#define hh putchar('\n')
#define kg putchar(' ')
#define debug puts("debug")
//#define int long long
//#define int __int128
namespace quickread{
    inline int read(){
        int x=0,f=1;char ch=getchar();
        while (ch<'0'||ch>'9'){if(ch=='-')f=-1;ch=getchar();}
        while (ch>='0'&&ch<='9'){x=(x<<3)+(x<<1)+ch-'0';ch=getchar();}
        return x*f;
    }
    inline void write(int x){
        if(x<0){putchar('-');x=-x;}
        if(x>9)write(x/10);
        putchar(x%10+'0');
    }
    inline string readstr(){
        char ch=getchar();string str="";
        while(!(ch>='0'&&ch<='9')&&!(ch>='a'&&ch<='z')&&!(ch>='A'&&ch<='Z')) ch=getchar();
        while((ch>='0'&&ch<='9')||(ch>='a'&&ch<='z')||(ch>='A'&&ch<='Z')){str+=ch;ch=getchar();}
        return str;
    }
    inline char readchar(){
        char ch=getchar();
        while(!(ch>='0'&&ch<='9')&&!(ch>='a'&&ch<='z')&&!(ch>='A'&&ch<='Z')) ch=getchar();
        return ch;
    }
}
using namespace quickread;
int n,m,bg,top,st[100010];
vector<int> p[510];
vector<int>::iterator it[100010];
bool vis[510][510];
void hierholzers(){
    for(int i=1;i<=n;i++){
        int d=p[i].size();
        if(d%2==1) {bg=i;break;}
    }
    for(int i=1;i<=n;i++){
        sort(p[i].begin(),p[i].end());
        it[i]=p[i].begin();
    }
    if(!bg){
        bg=510;
        for(int i=1;i<=n;i++)
            if(p[i].size()&&bg>i) bg=i; 
    }
}
void dfs(int u){
    while(it[u]!=p[u].end()){
        int v=*it[u];it[u]++;
        if(vis[u][v]) continue;
        vis[u][v]=vis[v][u]=1;
        dfs(v);
    }
    st[++top]=u;
}
signed main(){
//  ios::sync_with_stdio(0);
//  cin.tie(0);cout.tie(0);
    m=read();
    for(int i=1;i<=m;i++){
        int u=read(),v=read();
        p[u].push_back(v);
        p[v].push_back(u);
        n=max(n,max(u,v));
    }
    hierholzers();
    dfs(bg);
    for(int i=top;i>=1;i--) write(st[i]),hh;;
    return 0;
}

by fengzhaoyu @ 2024-05-01 15:09:47

考虑重边

#include<bits/stdc++.h>
using namespace std ;
int g[10005][10005],du[100004];
int m,n;
int ans[100005],tot;
void dfs(int u)
{
    for(int i=1;i<=n;i++)
    {
        if(g[u][i]>0)
        {
            g[u][i]--;
            g[i][u]--;
            dfs(i);
        }
    }
    ans[++tot]=u;
}
int main()
{
    cin>>m;
    for(int i=1;i<=m;i++)
    {
        int u,v;
        cin>>v>>u;
        g[v][u]++;g[u][v]++;
        du[v]++;
        du[u]++;
        n=max({v,u,n});     
    }
    int st=1;
    for(int i=1;i<=n;i++)
    {
        if(du[i]%2==1)
        {
            st=i;break;
        }
    }
    dfs(st);
    for(int i=tot;i>=1;i--)
    {
        cout<<ans[i]<<endl;
    }
    return 0;
}

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