_cheems_ckr_ @ 2024-05-03 23:09:23

#include<bits/stdc++.h>
using namespace std;
int n,k,ans=0,ans1=0,num=0,num1=0;
int main(){
    cin>>n>>k;
    for(int i=1;i<=n;i++){
        if(i%k==0){
            ans++;
            ans1+=i;
        }else{
            num++;
            num1+=i;
        }
    }
    double a,b;
    a=double(ans1/ans);
    b=double(num1/num);
    printf("%.1lf %.1lf",a,b);
    return 0;
}

by _cheems_ckr_ @ 2024-05-03 23:12:42

悬关
求大佬

by kmst_ayk @ 2024-05-03 23:42:11

第16,17行改成下面这样：

a=double(ans1)/ans;
b=double(num1)/num;

by cmask4869 @ 2024-05-03 23:43:45

@_cheemsckr 中间不用这么麻烦，这样就 ok 了：

for (int i=k ; i<=n ; i+=k) sum+=i ;

by _cheems_ckr_ @ 2024-05-04 09:51:46

哦，感谢大佬 @kmst_ayk @cmask4869

by abcd987654321 @ 2024-05-25 10:34:12

@_cheemsckr SB

by geyijin @ 2024-05-26 19:41:39

- 1.

****

by geyijin @ 2024-05-26 19:42:09

@abcd987654321 有没有素质