求助！！！！！！！

uua___ @ 2024-05-15 17:31:31

#include<bits/stdc++.h>
using namespace std;
int  a[1000000],b[1000000],c[1000000];
string x,y;
int la,lb,lc;
int main()
{
    cin>>x>>y;
    la=x.size();
    lb=y.size();
    for(int i=0;i<la;i++)
    {
        a[la-i]=x[i]-'0';
    }
    for(int i=0;i<lb;i++)
    {
        b[lb-i]=y[i]-'0';
    }
    lc=max(la,lb);
    for(int i=1;i<=lc;i++)
    {
        c[i]+=a[i]+b[i];
        c[i+1]=c[i]/10;
        c[i]=c[i]%10;
    }
    if(c[lc+1]>0) lc++;
    for(int i=lc;i>=1;i--)
    {
        cout<<c[i];
    }

    return 0;
}

by Crab_Tang @ 2024-05-15 17:39:11

@uua___ 一看你就是高精度写挂了。

by YONEX @ 2024-05-15 17:41:22

@Robots75 有没有可能是没有考虑负数 @uua___

by Crab_Tang @ 2024-05-15 17:43:51

@uua___ 不是，你这题有负数的大哥。你做高精度你去高精度A+b去；

by stylus @ 2024-05-15 17:58:03

@uua___ 不愧是牢大,so?

#include<bits/stdc++.h>
using namespace std;
int a,b;
int main(){
    cin>>a>>b;
    cout<<a+b<<endl;
    return 0;
}

发现一个好玩的：

&

by ZiruiLIU @ 2024-05-30 20:20:30

如此简单的题,你整这么麻烦，我20秒就能手写完：

#include<bits/stdc++.h>
  using namespase std;
  int main(){
  int a,b;
  cin>>a>>b;
  cout<<a+b;
  return 0;
  }

by heyuyan @ 2024-06-22 17:18:13

@ZiruiLIU 我也是

by mcturtle @ 2024-06-23 22:18:40

牢大，高精度是高精度，可是你忘判断负数了

by Andlewzheyao @ 2024-07-02 11:50:10

不是哥们，高精度也是这样写，牢大这次真坠机了

#include<bits/stdc++.h>
using namespace std;
int a[10000] = {0}, b[10000] = {0};
int main() {
    string js1, js2;
    cin >> js1 >> js2;
    int len1 = js1.size(), len2 = js2.size();
    for (int i = len1 - 1, j = 0; i >= 0; i--, j++) {
        a[j] = js1[i] - '0';
    }
    for (int i = len2 - 1, j = 0; i >= 0; i--, j++) {
        b[j] = js2[i] - '0';
    }

    int i = 0, x = 0;
    while ( i <= len1 || i <= len2 ) {
        b[i] += a[i] + x;
        x = b[i] / 10;
        b[i] %= 10;
        i++;
    }
    b[i] = x;
    while (b[i] == 0 && i != 0) i--;
    for (int j = i; j >= 0; j--) {
        cout << b[j];
    }
    cout << endl;
}