测试点1是一个成绩信息都为0的测试点，这个时候按原顺序输出q[0]的每个信息就好了，加个特判即可以
by some_die_young @ 2024-05-19 22:30:57
```cpp
#include<iostream>
#include<algorithm>
using namespace std;
const int N = 1010;
struct node{
int all;
string s;
int a,b,c;
}q[N];
bool cmp(node a,node b){
return a.all>b.all;
}
int cnt = 0;
int main(){
int t;
cin >>t;
for(int i=0;i<t;i++){
int all;
string s;
int a,b,c;
cin >> s >> a >> b >> c;
all = a+b+c;
q[i].all = all;
q[i].s = s;
q[i].a=a;
q[i].b=b;
q[i].c=c;
cnt += all;
}
if(cnt == 0){
cout <<q[0].s<<" "<<q[0].a<<" "<<q[0].b<<" "<<q[0].c;
return 0;
}
sort(q,q+t,cmp);
cout <<q[0].s<<" "<<q[0].a<<" "<<q[0].b<<" "<<q[0].c;
return 0;
}
``````
by some_die_young @ 2024-05-19 22:32:47
谢谢啦
by jason2024 @ 2024-05-20 17:16:16