peana @ 2024-05-20 16:55:53
#include<stdio.h>
#include<math.h>
#define ot 8*60
#define gc 10
int main()
{
int s,v;
double t,t1;
scanf("%d %d",&s,&v);
t=s/v+gc;
t1=ot-t;
while(t1<0)
{
t1+=24*60;
}
int hour=(int)floor(t1/60);
int min=(int)t1%60-1;
printf("%02d:%02d",hour,min);
return 0;
}
by glass_goldfish @ 2024-05-20 18:07:41
@peana AC代码来了。求加:https://www.luogu.com.cn/team/79073
#include<bits/stdc++.h>
using namespace std;
int s,v,sd,hh=7,mm=60;
int main()
{
cin>>s>>v;
if(s%v==0)sd=s/v;
else sd=s/v+1;
sd+=10;
int h=sd/60;
int m=sd%60;
if(h>hh)hh+=24;
int h1=hh-h;
int m1=mm-m;
if(m1==60){
m1=0;
h1++;
}
if(h1==24)h1=0;
if(h1==0){
cout<<"00:";
if(m1==0)cout<<"00";
else if(m1<10)cout<<"0"<<m1;
else cout<<m1;
}
else if(h1<10){
cout<<"0"<<h1<<":";
if(m1==0)cout<<"00";
else if(m1<10)cout<<"0"<<m1;
else cout<<m1;
}
else{
cout<<h1<<":";
if(m1==0)cout<<"00";
else if(m1<10)cout<<"0"<<m1;
else cout<<m1;
}
return 0;
}
by peana @ 2024-05-21 16:15:31
#include<stdio.h>
#include<math.h>
#define ot 8*60
#define gc 10
int main()
{
int s,v,t,t1,t2,hour,min;
scanf("%d %d",&s,&v);
t=s/v;
if(s%v==0)
{t2=t+gc;}
else
{t2=t+gc+1;}
t1=ot-t2;
while(t1<0)
{
t1+=24*60;
}
hour=t1/60;
min=t1%60;
printf("%02d:%02d\n",hour,min);
return 0;
}
终于想出来了