满江红QAQ

lzy13915136909 @ 2024-05-20 21:06:00

#include<bits/stdc++.h>
using namespace std;
int main()
{
    int n,a[1005],b[1005];
    cin>>n;
    for(int i=0;i<n;i++)
        cin>>a[i]>>b[i];
    for(int i=0;i<n;i++)
    {
        if(a[i]-b[i]>0.05)
            cout<<"better"<<endl;
        else
        {
            if(b[i]-a[i]>0.05)
                cout<<"worse"<<endl;
            else
                cout<<"same"<<endl;
        }
    }
    return 0;
}

by XuYueming @ 2024-05-20 21:20:40

@abc1234shi ？他用两个循环有错吗

by TLE_AK @ 2024-05-20 21:20:48

@lzy13915136909 你先要保存鸡尾酒（第一次输入）的率啊

by lzy13915136909 @ 2024-05-20 21:21:35

@abc1234shi 依旧满江红......

code：

#include<bits/stdc++.h>
using namespace std;
int n,a[1005],b[1005];
int main()
{
    cin>>n;
    for(int i=0;i<n;i++)
    {
        cin>>a[i]>>b[i];
        for(int i=0;i<n;i++)
        {
            if(a[i]-b[i]>0.05)
                cout<<"better"<<endl;
            else
            {
                if(b[i]-a[i]>0.05)
                    cout<<"worse"<<endl;
                else
                    cout<<"same"<<endl;
            }
        }
    }
    return 0;
}

by March7thDev @ 2024-05-20 21:22:11

对，先存率，在判断

by abc1234shi @ 2024-05-20 21:22:14

@lzy13915136909 你再设两个变量x,y,z，输入x,y。z=x×1.00/y×1.00;这是标准，然后后面的你再设一个变量s,s=a[i]×1.00/b[i]×1.00，将z和s进行比较

by TLE_AK @ 2024-05-20 21:23:21

@lzy13915136909 1.两个循环也可以，否则把i改了 2.应该比较概率，也就是b[i]/a[i]与b[1]/a[1]的差

by lzy13915136909 @ 2024-05-20 21:24:30

@abc1234shi @红黑树 @Doraemon @XuYueming @TLE_AK 脑子要explode了...... I do not understand思密达

by abc1234shi @ 2024-05-20 21:24:38

其实我觉得数组没必要

by abc1234shi @ 2024-05-20 21:24:59

@lzy13915136909 你第二个循环不要了

by TLE_AK @ 2024-05-20 21:25:33

@abc1234shi 随便吧，反正不卡空间时间（