lyx8094 @ 2024-06-06 10:54:57
#include<bits/stdc++.h>
using namespace std;
int main(){
int n;cin>>n;
int a[1001],i;
for(i=1;i<=n;i++){
cin>>a[i];
}
sort(a,a+n+1);
double sum=0;
for(i=2;i<n;i++){
sum=sum+a[i];
}printf("%.2f",sum/(n-2));
}
by ltl0825 @ 2024-06-06 10:59:07
@lyx8094 应该是sort(a+1,a+1+n);
by SCP035 @ 2024-06-06 12:25:14
#include<bits/stdc++.h>
using namespace std;
int main(){
int n,a[10001],s=1,j=1000,sum=0;
cin>>n;
for(int i=0; i<n; i++){
cin>>a[i];
sum=sum+a[i];
}
for(int i=0; i<n; i++){
s = max(s,a[i]);
j = min(j,a[i]);
}
sum = sum-s-j;
cout<<fixed<<setprecision(2)<<sum*1.0/(n-2);
return 0;
}
by SCP035 @ 2024-06-06 12:25:54
@lyx8094 我用的循环
by coderzhx @ 2024-06-06 21:32:57
#include <iostream>
using namespace std;
long p = -66666;
long q = 88888;
double a[50000];
double n;
double sum;
int main() {
cin >> n;
for (int i = 1; i <= n; i++) {
cin >> a[i];
sum += a[i];
if (a[i] > p) {
p = a[i];
}
if (a[i] < q) {
q = a[i];
}
}
printf("%.2lf", (sum - (p + q)) / (n - 2) * 1.0);
return 0;
}
@ltl0825
by HuangSiHan3116 @ 2024-07-19 08:51:42
@lyx8094 这样就行。本人很垃圾。不喜勿喷。
#include<bits/stdc++.h>
using namespace std;
int main(){
double n,m==11,M==-1,sum;
cin>>n;
for(int i=1;i<=n;++i){
int x;
cin>>x;
sum+=x;
if(x>M){
M=x;
}
if(x<m){
m=x;
}
}
printf("%.2lf",(sum-M-m)/(n-2.0));
return 0;
}