guoen23 @ 2024-06-22 16:17:33
#include<bits/stdc++.h>
using namespace std;
int a,b,f,g = 0;
long long c[1000005],d[100005] = {'0'};
bool e = false;
int main(){
cin>>a>>b;
for(int i = 0;i<a;i++){
cin>>c[i];
}
for(int i = 0;i<b;i++){
cin>>d[i];
for(int j = 0;j <a;j++){
if(c[j] == d[i]){
f = j + 1;
e = true;
break;
}
}
if(e == false){
cout<<-1;
}
else{
cout<<f<<" ";
e = false;
}
}
}
本人写了代码,样例过了,提交全是TLE和WA(虽然我知道这是暴力算法)[求解(ToT)/~~~]
by xQWQx @ 2024-06-22 16:39:28
@guoen23 用二分
by dtw35l @ 2024-06-26 15:36:42
@guoen23
第21行
cout<<-1;
改成
cout<<-1<<" ";
每次输出都应该后缀空格
解决TLE要二分
by guoen23 @ 2024-06-29 15:45:24
@dtw35l 好的,就AC两个[/(ㄒoㄒ)/~~]
by Enmin @ 2024-07-05 20:32:07
@guoen23 二分