_Liyx_ @ 2024-07-10 11:45:06
写的BFS,已经优化不了了,有没有大佬帮我看看
#include <bits/stdc++.h>
using namespace std;
int n,m;
string mp[1005];
bool vis[1005][1005];
int x,y;
int ans;
int dx[5]={1,0,-1,0},dy[5]={0,1,0,-1};
struct node{
int x,y;
};
int aa[100005];
int bb[1005][1005];
void bfs(int id){
memset(vis,0,sizeof(vis));
ans=1;
queue<node> q;
q.push((node){x,y});
vis[x][y]=1;
while(!q.empty()){
node now=q.front();
q.pop();
for(int i=0;i<4;i++){
int xx=now.x+dx[i],yy=now.y+dy[i];
if(xx>=0&&xx<n&&yy>=0&&yy<n&&vis[xx][yy]==0&&(mp[xx][yy]-'0'+mp[now.x][now.y]-'0')==1){
vis[xx][yy]=1;
q.push((node){xx,yy});
bb[xx][yy]=id;
ans++;
}
}
}
}
int main(){
cin>>n>>m;
for(int i=0;i<n;i++){
cin>>mp[i];
}
for(int i=1;i<=m;i++){
cin>>x>>y;
x--;
y--;
if(bb[x][y]!=0){
cout<<aa[bb[x][y]]<<"\n";
continue;
}
bfs(i);
aa[i]=ans;
cout<<ans<<"\n";
}
return 0;
}
by wscmh @ 2024-07-10 12:00:28
#include <bits/stdc++.h>
using namespace std;
const size_t MaxN = 1050;
size_t N, M;
string Map[MaxN];
int dx[] = {+1, -1, +0, +0};
int dy[] = {+0, +0, +1, -1};
unsigned int Parent[MaxN * MaxN];
unsigned int Size[MaxN * MaxN];
inline unsigned int Index(const unsigned int &i, const unsigned int &j) {
return (i - 1) * N + j;
}
unsigned int Find(const unsigned int &v) {
return Parent[v] == v ? v : Parent[v] = Find(Parent[v]);
}
int main() {
cin >> N >> M;
for (size_t i = 1; i <= N; ++i) {
cin >> Map[i];
Map[i] = "0" + Map[i];
}
for (size_t i = 1; i <= N * N; ++i)
Parent[i] = i, Size[i] = 1;
for (size_t i = 1; i <= N; ++i)
for (size_t j = 1; j <= N; ++j)
for (size_t k = 0; k != 4; ++k) {
int a = i + dx[k];
int b = j + dy[k];
if (a >= 1 && a <= N && b >= 1 && b <= N)
if (Map[i][j] != Map[a][b]) {
unsigned int x = Find(Index(i, j));
unsigned int y = Find(Index(a, b));
if (x != y) {
Parent[y] = x;
Size[x] += Size[y];
}
}
}
while (M--) {
int a, b;
cin >> a >> b;
cout << Size[Find(Index(a, b))] << endl;
}
return 0;
}
by wscmh @ 2024-07-10 12:00:39
@Liyx
by feather20120426 @ 2024-07-10 16:22:02
@Liyx,你的代码可以在算出每一个连通块的大小是多少事,把连通块的每一项赋值成连通块的大小