10分，样例过了，求助

qixiuyuan123 @ 2024-07-14 11:45:45

#include<iostream>
using namespace std;
int t;
char a[12],mod[12]="0123456789X";
int main()
{
    cin>>a;
    for(int i=0,j=0;i<12;i++)
        if(a[i]=='-')
            continue;
        else
            t+=(a[i]-'0')*++j;
    if(mod[t%11]==a[12])
        printf("\nRight");
    else
    {
        a[12]=mod[t%11];
        cout<<a;
    }
    return 0;
}

by Phoenix114514 @ 2024-07-14 12:05:40

#include<bits/stdc++.h>
using namespace std;
string s;
int n,sum,k=1;
int main(){
    cin>>s;
    char mod[12]={'0','1','2','3','4','5','6','7','8','9','X'};
    for (int i=0;i<12;i++){
        if (s[i]!='-')sum=sum+(s[i]-'0')*(k++);
    }

    if (mod[sum%11]==s[12])cout<<"Right";
    else{
        s[12]=mod[sum%11];
        cout<<s;
    }
    return 0;
}

by Phoenix114514 @ 2024-07-14 13:45:11

@qixiuyuan123 错误一： for 循环最好加上大括号。

错误二： printf 前面为什么要有 \n 换行呢？

#include<bits/stdc++.h>
using namespace std;
int t;
char mod[12]={'0','1','2','3','4','5','6','7','8','9','X'};
string a;
int main(){
    cin>>a;
    for(int i=0,j=0;i<12;i++){
        if(a[i]=='-')continue;
        else t+=(a[i]-'0')*++j;
    }
    if(mod[t%11]==a[12])printf("Right");
    else{
        a[12]=mod[t%11];
        cout<<a;
    }
    return 0;
}

by Phoenix114514 @ 2024-07-14 15:03:51

@qixiuyuan123 rt

by qixiuyuan123 @ 2024-07-14 16:42:57

谢谢大佬（但是不加花括号能过），关了