70分求调

P5740 【深基7.例9】最厉害的学生

``` #include<cstdio> #include<iostream> using namespace std; string name[1005]; int cg[1005],mg[1005],eg[1005]; int main(){ int n,max=-999999,t; scanf("%d",&n); for(int a=0;a<n;a++)cin>>name[a]>>cg[a]>>mg[a]>>eg[a]; for(int b=0;b<n;b++){ if(cg[b]+mg[b]+eg[b]>max){ max=cg[b]+mg[b]+eg[b]; t=b; } } cout<<name[t]<<" "<<cg[t]<<" "<<mg[t]<<" "<<eg[t]; return 0; } ```
by zml1029 @ 2024-07-30 12:33:27


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