__F__ @ 2024-07-16 14:52:06

#include<bits/stdc++.h> 
using namespace std;
int main(){
    int m,k,s=0;
    cin>>m>>k;
    int t=m;
    while(t!=0){
        if(t%10==3){
            s++;
        }
        t=t/10;
    }
    if(s==k&&m%19==0)
     {
        cout<<"YES"; 
     }else{
        cout<<"NO";
     }
     return 0;
}

by rain_wu @ 2024-07-16 15:01:41

题目上说是10^15，而int最大值是2^31-1,也就是2147483647,2147483647<1000000000000000,那么就要开long long。

by 枫原万叶 @ 2024-07-16 15:18:10

@ yuhan09

怎么说你也用不了long long。

最多弄成这样70分，把判断条件改一下。

#include <bits/stdc++.h>
using namespace std;

int main() {
    long long m, k, s = 0;
    cin >> m >> k;
    int t = m;
    while (t != 0) {
        if (t % 10 == 3) {
            s++;
        }
        t = t / 10;
    }
    if (s == k) {
        cout << "YES";
    } else {
        cout << "NO";
    }
    return 0;
}

还是需要用字符串才行。

#include <bits/stdc++.h>
using namespace std;

int main() {
    string m;
    int k;
    cin >> m;
    cin >> k;
    for (int i = 0; i < m.size(); i++) {
        if (m[i] == '3')
            k--;
    }
    if (k == 0)
        cout << "YES";
    else
        cout << "NO";
    return 0;
}

这样就可以了

by Z_Zh @ 2024-07-16 15:22:03

@yuhan09 long long

include<bits/stdc++.h>

using namespace std; const int N=1e6+10; int main(){ long long n,s=0,a,b,c,m,k; cin>>m>>k; while(m!=0){ a=m%10;m/=10; if(a==3) s++;

}
if(s==k){
    cout<<"YES";
    return 0;
}
else {
    cout<<"NO";
}
return 0;

}

by playing_game @ 2024-07-16 16:08:45

@yuhan09 sdsdgg

by fangyuhan01 @ 2024-07-19 21:07:39

不是吧，你是另一个oj复制过来的吧

by fangyuhan01 @ 2024-07-19 21:09:51

题目没要求m要被19整除，把“&&m%19==0”删掉

by fangyuhan01 @ 2024-07-19 21:10:52

还要开

long long

by aaaaaa238 @ 2024-07-20 19:04:09

事实证明，不开long long他的确得见祖宗啊！接下来呈上我的AC 代码

#include <bits/stdc++.h>
using namespace std;
unsigned long long a;
int b;

bool jc(unsigned long long x, int y){
    int cnt = 0;
    while(x){
        int cxk = x % 10;
        if(cxk == 3) cnt++;
        x /= 10;
    }
    if(cnt == y) return true;
    return false;
}

int main(){
    cin >> a >> b;
    if(jc(a, b)) cout << "YES" << endl;
    else cout << "NO" << endl;
    return 0;
}