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P5740 【深基7.例9】最厉害的学生

注释忽略不理,因为我一个cpp文件用好几次,然后写的一些注释
by zkszks @ 2024-07-17 10:27:36


把n数组改成一维的,后面的[10001]删掉,输入时输入n[i],其他不用动
by Cailen @ 2024-07-17 10:32:51


@[zkszks](/user/670314) 结构体+排序 ```cpp #include<bits/stdc++.h> #include<string> using namespace std; struct student{ string name; int a,b,c,d; }; student a[1005]; int main(){ int n; cin>>n; for(int i=1;i<=n;i++){ cin>>a[i].name; cin>>a[i].a>>a[i].b>>a[i].c; a[i].d=a[i].a+a[i].b+a[i].c; } for(int i=n-1;i>0;i--){ for(int j=1;j<=i;j++){ if(a[j].d<a[j+1].d){ swap(a[j],a[j+1]); } } } cout<<a[1].name<<" "<<a[1].a<<" "<<a[1].b<<" "<<a[1].c; return 0; } ``` 求关注
by fire_flies @ 2024-07-17 10:33:26


@[zkszks](/user/670314) 可以试试用结构体来储存变量
by fire_flies @ 2024-07-17 10:34:33


@[zkszks](/user/670314) 求关 ```c #include <bits/stdc++.h> using namespace std; struct abc{ string name; int all_subject,chinese,math,english; int id; }a[11100]; bool cmp(abc a,abc b) { if(a.all_subject==b.all_subject){ return a.id<b.id; } return a.all_subject>b.all_subject; } int main() { int t1,t2,t3; int n; string s; cin >> n; for(int i=1;i<=n;i++){ cin >>s>> t1 >> t2 >> t3; a[i].name = s; a[i].chinese = t1; a[i].math = t2; a[i].english = t3; a[i].all_subject=t1+t2+t3; a[i].id=i; } sort(a+1,a+1+n,cmp); cout << a[1].name << " "<<a[1].chinese; cout << " " << a[1].math << " " << a[1].english; } ```
by Maisie586_ @ 2024-07-17 10:40:30


@[fire_flies](/user/1360902) 我试试
by zkszks @ 2024-07-17 11:19:37


@[Cailen](/user/1315276) 我看看
by zkszks @ 2024-07-17 11:20:55


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