爆0求助

zkszks @ 2024-07-17 10:26:32

#include <iostream>
//#include <iomanip>
#include <algorithm>
#include <string>

using namespace std;
string n[10001][10001];
int main(){
    int a,b[10001],c[10001],d[10001],m[10001];
    cin>>a;
    for(int i=0;i<a;i++){
        cin>>n[i][10001]>>b[i]>>c[i]>>d[i];
        m[i]=b[i]+c[i]+d[i];

        for(int o=0;o<i;o++){
            if(m[i]<m[o]){
                swap(m[o],m[i]);
                swap(n[o],n[i]);
                swap(b[o],b[i]);
                swap(c[o],c[i]);
                swap(d[o],d[i]);
            }
        }
    }
    cout<<n[a-1][10001]<<" "<<b[a-1]<<" "<<c[a-1]<<" "<<d[a-1];

}
//1090k 364x=n
//x x+k,x+2k x+3k x+4k x+5k x+6k   52(21k+7x)=1456 
//21k+7x=119

by zkszks @ 2024-07-17 10:27:36

注释忽略不理，因为我一个cpp文件用好几次，然后写的一些注释

by Cailen @ 2024-07-17 10:32:51

把n数组改成一维的，后面的[10001]删掉，输入时输入n[i]，其他不用动

by fire_flies @ 2024-07-17 10:33:26

@zkszks 结构体+排序

#include<bits/stdc++.h> 
#include<string> 
using namespace std;
struct student{
string name;
int a,b,c,d;
};
student  a[1005];
int main(){
    int n;
    cin>>n;
    for(int i=1;i<=n;i++){
        cin>>a[i].name;
        cin>>a[i].a>>a[i].b>>a[i].c;
        a[i].d=a[i].a+a[i].b+a[i].c;
    }
    for(int i=n-1;i>0;i--){
        for(int j=1;j<=i;j++){
            if(a[j].d<a[j+1].d){
                swap(a[j],a[j+1]);
            }
        }
    }
    cout<<a[1].name<<" "<<a[1].a<<" "<<a[1].b<<" "<<a[1].c;
    return 0;
} 

求关注

by fire_flies @ 2024-07-17 10:34:33

@zkszks 可以试试用结构体来储存变量

by Maisie586_ @ 2024-07-17 10:40:30

@zkszks 求关

#include <bits/stdc++.h>

using namespace std;
struct abc{
    string name;
    int all_subject,chinese,math,english;
    int id;
}a[11100];
bool cmp(abc a,abc b)
{
    if(a.all_subject==b.all_subject){
        return a.id<b.id;
    } 
    return a.all_subject>b.all_subject; 
}

int main() {
    int t1,t2,t3;
    int n;
    string s; 
    cin >> n;
    for(int i=1;i<=n;i++){
        cin >>s>> t1 >> t2 >> t3;
        a[i].name = s;
        a[i].chinese = t1;
        a[i].math = t2;
        a[i].english = t3;
        a[i].all_subject=t1+t2+t3;
        a[i].id=i;
    } 
    sort(a+1,a+1+n,cmp);
    cout << a[1].name << " "<<a[1].chinese;
    cout << " " << a[1].math << " " << a[1].english; 
}

by zkszks @ 2024-07-17 11:19:37

@fire_flies 我试试

by zkszks @ 2024-07-17 11:20:55

@Cailen 我看看