zjy0419 @ 2024-07-21 20:51:47
#include <bits/stdc++.h>
using namespace std;
int main() {
int n;
cin >> n;
long long a[n + 1],b,c;
a[0] = 1;
a[1] = 1;
for (int i = 1; i < n; i++) {
a[i + 1] = a[i - 1] + a[i];
}
cout << abs(a[n]);
}
by cancan1030 @ 2024-07-21 20:58:51
数据太大,得用高精度加法
by zjy0419 @ 2024-07-21 21:02:15
Ok,尝试一下。
by zjy0419 @ 2024-07-21 22:56:38
OK了,栓Q
by _Monkey_King_ @ 2024-08-21 09:51:35
采纳了