hanss6 @ 2024-07-23 20:55:18
#include <bits/stdc++.h>
using namespace std;
#define int long long
#define ls (p << 1)
#define rs (ls | 1)
#define len(p) (t[p].r - t[p].l + 1)
const int N = 5e5 + 5;
int n, m, a[N];
struct Info{
int l, r, sum, lmx, rmx, ans;
} t[N << 2];
Info operator + (const Info &lhs, const Info &rhs) {
Info res;
res.ans = max(max(lhs.ans, rhs.ans), lhs.rmx + rhs.lmx);
res.lmx = max(lhs.lmx, lhs.sum + rhs.lmx);
res.rmx = max(rhs.rmx, rhs.sum + lhs.rmx);
res.sum = lhs.sum + rhs.sum;
return res;
}
void pushup(int p) {
t[p] = t[ls] + t[rs];
// cout << p << " "<<endl;
}
void build(int p, int l, int r) {
t[p].l = l, t[p].r = r;
// cout << p << ' ' << t[p].l << ' '<< t[p].r << endl;
if (l == r) {
t[p].sum = t[p].lmx = t[p].rmx = t[p].ans = a[l];
return;
}
int mid = (l + r) >> 1;
build(ls, l, mid);
build(rs, mid + 1, r);
pushup(p);
}
void change(int p, int pos, int x) {
if (t[p].l == t[p].r) {
t[p].sum = t[p].lmx = t[p].rmx = t[p].ans = x;
return;
}
int mid = (t[p].l + t[p].r) >> 1;
if (mid >= pos) change(ls, pos, x);
if (mid < pos) change(rs, pos ,x);
pushup(p);
}
Info query(int p, int l, int r) {
if (t[p].l >= l && t[p].r <= r) return t[p];
int mid = (t[p].l + t[p].r) >> 1;
if (mid >= l && mid < r) return query(ls, l, r) + query(rs, l, r);
if (l <= mid) return query(ls, l, r);
return query(rs, l, r);
}
signed main() {
ios::sync_with_stdio(0), cin.tie(0), cout.tie(0);
cin >> n >> m;
for (int i = 1; i <= n; i++) {
cin >> a[i];
}
build(1, 1, n);
while (m--) {
int k;
cin >> k;
if (k == 1) {
int l, r;
cin >> l >> r;
cout << query(1, min(l, r), max(l, r)).ans << endl;
} else {
int p, x;
cin >> p >> x;
change(1, p, x);
}
}
return 0;
}
by ericloo0921 @ 2024-07-30 20:32:44
题目说可能出现a大于b的情况,在1操作时需要判断 if (l>r) swap(l,r);
by hanss6 @ 2024-08-04 12:43:13
@ericloo0921 我调用函数的时候注意到了,l取的min(l,r) r取的max(l,r)