？？？

mkd123 @ 2024-07-29 08:05:51

#include <iostream>  
#include <string>  
#include <algorithm>
using namespace std;  

int main()  
{  
    string b;  
    getline(cin, b);  
    reverse(b.begin(), b.end());  
    cout <<b;  
    return 0;  
}

by HFZ20111110 @ 2024-07-29 08:10:50

@mkd123 万一带前导0你也敢输出？

by HFZ20111110 @ 2024-07-29 08:11:31

@mkd123 sorry，好像没有前导0

by HFZ20111110 @ 2024-07-29 08:13:06

@mkd123 我要不要告诉你，其实可以这样做

#include<bits/stdc++.h>
using namespace std;
char a,b,c,d;
int main(){
    scanf("%c%c%c.%c",&a,&b,&c,&d);
    printf("%c.%c%c%c",d,c,b,a); 
    return 0; 
} 

by tianenyang @ 2024-07-29 11:34:18

直接用string之后循环减减输出不好吗 strings;cin>>s;for(int i=s.size()-1;i>=0;i--)输出

by tianenyang @ 2024-07-29 11:36:02

#include<bits/stdc++.h>
using namespace std;
int main(){
    string s;
    cin>>s;
    for(int i=s.size()-1;i>=0;i--) cout<<s[i];
    return 0;
}

这样试试

by mkd123 @ 2024-07-29 20:14:15

@HFZ20111110 嗷嗷，感谢

by mkd123 @ 2024-07-29 20:15:17

@tianenyang ok，感谢

by tianenyang @ 2024-07-30 07:39:36

@mkd123 ok

by gongxiaokaoyan @ 2024-08-27 16:32:11

啊？我也是这么写的，就输入不同

#include <bits/stdc++.h>
using namespace std;
string s;
int main(){
    cin >> s;
    reverse(s.begin(), s.end());
    cout << s;
    return 0;
}