样例输出1

P1216 [USACO1.5] [IOI1994]数字三角形 Number Triangles

Alananan @ 2024-07-31 14:24:06

#include<iostream>
#include<cstdio>
using namespace std;
const int N = 1010;
int n,f[N][N];
int main(){
    scanf("%d",&n);
    for(int i = 1;i <= n;i++){
        for(int j = 1;j <= i;j++){
            scanf("%d",&f[i][j]);
        }
    }
    for(int i = 2;i <= n;i++){
        for(int j = 1;j <= i;j++){
            f[i][j] = max(f[i-1][j-1],f[i-1][j]);
        }
    }
    int maxx = -1;
    for(int i = 1;i <= n;i++){
        if(f[N][i] > maxx){
            maxx = f[N][i];
        }
    }
    cout<<maxx<<endl;

    return 0;
}

样例输出 1 怎么办啊QWQ


by hermione_wqx @ 2024-07-31 14:50:53

求关


#include<bits/stdc++.h>
using namespace std;
int a[1005][1005],dp[1005][1005];
int main(){
    int n;
    cin>>n;
    for(int i=1;i<=n;i++){
        for(int j=1;j<=i;j++)cin>>a[i][j];
    }
    dp[1][1]=a[1][1];
    for(int i=2;i<=n;i++){
        for(int j=1;j<=i;j++){
            dp[i][j]=max(dp[i-1][j],dp[i-1][j-1])+a[i][j];
        }
    }
    int maxx=0;
    for(int i=1;i<=n;i++){
        if(dp[n][i]>=maxx)maxx=dp[n][i];
    }
    cout<<maxx;
    return 0;
}

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