junbeder @ 2024-08-02 18:13:17
by junbeder @ 2024-08-02 18:14:42
我的代码:```
using namespace std; signed main(){ double x,y; cin>>x; if(0<=x<=5) y=-x+2.5; else if(5<=x<10) else if(10<=x<20) y=x/2-1.5; printf("%.3lf",y) return 0; }
by junbeder @ 2024-08-02 18:15:23
# include<bits/stdc++h>
using namespace std;
signed main(){
double x,y;
cin>>x;
if(0<=x<=5) y=-x+2.5;
else if(5<=x<10)
else if(10<=x<20) y=x/2-1.5;
printf("%.3lf",y)
return 0;
}
by hyl_____ @ 2024-08-02 18:15:25
? 代码呢
by haimingbei @ 2024-08-02 18:27:40
@junbeder 要用&&(逻辑运算)
by haimingbei @ 2024-08-02 18:28:50
@junbeder &&表示并且 AC,求关
#include<bits/stdc++.h>
using namespace std;
int main()
{
double n, m;
cin >> n;
if(n >= 0 && n < 5)
{
cout << fixed << setprecision(3) << 2.5 - n;
return 0;
}
if(n >= 5 && n < 10)
{
cout << fixed << setprecision(3) << 2.0 - (n-3.0)*(n - 3.0) * 1.5;
return 0;
}
cout << fixed << setprecision(3) << n / 2.0 - 1.5;
}
by junbeder @ 2024-08-02 18:31:01
# include<bits/stdc++h>
using namespace std;
signed main(){
double x,y;
cin>>x;
if(0<=x<=5) y=-x+2.5;
else if(5<=x<10)
else if(10<=x<20) y=x/2-1.5;
printf("%.3lf",y)
return 0;
}
by junbeder @ 2024-08-02 18:31:49
@haimingbei谢谢,已关。
by youthiscoming @ 2024-08-24 07:42:12
@haimingbei
又在刷水题
by haimingbei @ 2024-08-24 09:26:35
@youthiscoming 你这么早就在线了?(7点???)
by youthiscoming @ 2024-08-24 18:03:37
@haimingbei
趁早刷题,早点红名