Jiang2012 @ 2024-08-04 11:14:57
#include<bits/stdc++.h>
using namespace std;
int main()
{
int n,a;
float ans;
cin>>n;
for(int i=1;i<=n;i++)
{
cin>>a;
ans+=a*1.0/n;
}
printf("%0.2lf",ans);
return 0;
}
by HeartBeast @ 2024-08-04 11:24:21
先算和再除n,ans开double
#include<bits/stdc++.h>
using namespace std;
int main()
{
int n;
double ans,a;
cin>>n;
for(int i=1;i<=n;i++){
cin>>a;
ans+=a*1.0;
}
printf("%0.2lf",ans/n);
return 0;
}