ziyang22 @ 2024-08-11 20:33:35
#include<stdio.h>
int main (void){
long k,n,count = 0;
scanf("%ld %ld",&n,&k);
while(n/k != 0){
n = n-k+1;
printf("n = %ld\n",n);
count += k;
printf("count = %ld\n",count);
}
count += n;
printf("%ld",count);
return 0;
}
这是提交上去为100的解,但是逻辑上应该把while里面的条件改成n/k>=0才对呀?
by Elaina_0 @ 2024-08-11 20:55:10
@ziyang22
除到最后 n=0
或 n<0&&(-n<k)
时仍会再加 k
导致多算了几遍。
求关喵~