Innate_Joker @ 2024-08-13 12:23:44
#include <cstring>
#include <iostream>
using namespace std;
int main() {
char pinn[1000];
cin.getline(pinn,1000);
int len = strlen(pinn);
for(int i = 0; i < len; i ++ ) {
char pin[100];
int j = i,lenn = 0;
while(pinn[j] != ',') {
pin[lenn ++ ] = pinn[j ++ ];
}
i = j;
bool small = false;
bool big = false;
bool special = false;
bool number = false;
for(int p = 0; p < strlen(pin); p ++ ) {
if(pin[p] == '!' || pin[p] == '@' ||
pin[p] == '#' || pin[p] == '$') {
special = true;
}
if(pin[p] >= 'a' && pin[p] <= 'z') {
small = true;
}
if(pin[p] >= 'A' && pin[p] <= 'Z') {
big = true;
}
if(pin[p] >= '0' && pin[p] <= '9') {
number = true;
}
}
short total = 0;
if(small == true) {
total ++;
}
if(big == true) {
total ++;
}
if(number == true) {
total ++;
}
if(special == true && total >= 2 && lenn >= 6 && lenn <= 12) {
cout << pin << ' ' << special << ' ' << total << endl;
}
}
return 0;
}
Error:
Runtime Error.
Received signal 11: Segmentation fault with invalid memory reference.
Chinese:
运行时出错。
接收到信号 11:分段故障,内存引用无效。
by lin20081016 @ 2024-08-13 12:35:50
最后一串密码后没有逗号,第11行再以逗号为判断就会卡住吧
by Fractured_Angel @ 2024-08-13 12:40:56
不知道这 GESP 到底有啥用。。。
by Maisie586_ @ 2024-08-13 12:41:47
@Fractured_Angel 可以免一关CSP((
by zts201210 @ 2024-08-13 12:42:52
@lin20081016 对
while(pinn[j] != ',' && j < len)
@Innate_Joker
by zts201210 @ 2024-08-13 12:43:49
@Maisie586_ 但是有点贵((
by Innate_Joker @ 2024-08-13 13:01:41
感谢。 此贴结。