ye_you @ 2024-08-14 14:45:01
sqrt有点玄学（返回的double），一定要先强制转换为整数再判断。
by goodwepb1 @ 2024-08-14 14:56:15
pow((int)sqrt(a[i] + a[j])像这样饥渴
by fengzhaoyu @ 2024-08-18 15:50:10
6
by rogerfrz @ 2024-08-21 15:56:36
if(sqrt(a[i]+a[j])long(sqrt(a[i]+a[j]))==0)
by caiyunlang @ 2024-08-22 15:30:58
无语
by __Deng_Rui_Song__ @ 2024-09-06 08:21:30
@ye_you 不如预处理（大雾
by Youmh @ 2024-09-06 22:45:20
感谢大佬