P5707 70分求助

P5707 【深基2.例12】上学迟到

@[NewMinecraft](/user/989044) 由于数据的离谱性,yyy有可能昨天开始赶路。
by dongzirui0817 @ 2024-08-18 11:53:44


@[NewMinecraft](/user/989044) 万一是要在上一天出发才不能迟到呢?
by jiangmuhangpphooga @ 2024-08-18 11:54:26


@[NewMinecraft](/user/989044) 可以这样判断yyy昨天赶路 ```c time=ceil(1.0*s/v)+10; x=480-time; if(x<0){ //自己写 } ............. ```
by jiangmuhangpphooga @ 2024-08-18 11:57:46


```cpp #include<bits/stdc++.h> using namespace std; double s,v,m; int n,a,t,b; int main(){ cin>>s>>v; n=8*60+24*60; t=ceil(s/v)+10; n-=t; if(n>=24*60) n-=24*60; b=n%60; a=n/60; if(a<10){ if(b<10)cout<<0<<a<<:0<<b; else cout<<0<<a<<":"<<b; }else{ if(b<10) cout<<a<<":0"<<b; else cout<<a<<":"<<b; } return 0; } ``` 以A求关
by jzm_2024 @ 2024-08-18 12:16:02


谢谢各位回答
by NewMinecraft @ 2024-08-19 11:36:34


@[NewMinecraft](/user/989044) ac了吗?
by jiangmuhangpphooga @ 2024-08-19 11:41:24


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