a20111127 @ 2024-08-19 20:49:36

by a20111127 @ 2024-08-19 20:51:03

include<bits/stdc++.h>

using namespace std; int main(){ double s,v; cin>>s>>v; double t=s/v; if(t-(int)t==0&&t<=1430){ int t1=int(t)+10; if(t1%60>50){ cout<<7-(t1/60)<<":0"<<60-(t1%60);} else{ cout<<7-(t1/60)<<":"<<60-(t1%60); } } else if(t-(int)t!=0&&t<=1430){ int t1=int(t)+11; if(t1%60>50){ cout<<7-(t1/60)<<":0"<<60-(t1%60);} else{ cout<<7-(t1/60)<<":"<<60-(t1%60); } } return 0; } _

_

**~~ _

• #include<bits/stdc++.h>
  using namespace std;
  int main(){
  double s,v;
  cin>>s>>v;
  double t=s/v;
  if(t-(int)t==0&&t<=1430){
      int t1=int(t)+10;
      if(t1%60>50){
      cout<<7-(t1/60)<<":0"<<60-(t1%60);}
      else{
      cout<<7-(t1/60)<<":"<<60-(t1%60);
      }
  }
  else if(t-(int)t!=0&&t<=1430){
      int t1=int(t)+11;
      if(t1%60>50){
      cout<<7-(t1/60)<<":0"<<60-(t1%60);}
      else{
      cout<<7-(t1/60)<<":"<<60-(t1%60);
      }
  }
  return 0;
  }

  ~~** _

by Grammar__hbw @ 2024-08-19 20:52:04

希望更丰富的展现？使用 Markdown、KaTeX。

by a20111127 @ 2024-08-19 20:53:07

代码是这个，请各位神犇帮帮我吧，求求了

by Emil_ @ 2024-08-19 20:54:01

@a20111127

来了宝贝，三剑客拜见，求关求关qwq，ac代码：

#include <bits/stdc++.h>

using namespace std;
double s,v,m;
int n,a,t,b;
int main(){
    cin>>s>>v;
    n=8*60+24*60;
    t=ceil(s/v)+10;
    n=n-t;
    if(n>=24*60) n-=24*60;
    b=n%60;
    a=n/60;
    if(a<10){
        if(b<10) cout<<"0"<<a<<":0"<<b;
        else cout<<"0"<<a<<":"<<b;
    }else{
        if(b<10) cout<<a<<":0"<<b;
        else cout<<a<<":"<<b;
    }
    return 0;
}

by Dejected @ 2024-08-19 20:54:15

@a20111127

来了宝贝，AC代码来啦 求关qwq

#include<bits/stdc++.h>
using namespace std;
double s,v,m;
int n,a,t,b;
int main(){
    cin>>s>>v;
    n=8*60+24*60;
    t=ceil(s/v)+10;
    n=n-t;
    if(n>=24*60){
        n-=24*60;
    }
    b=n%60;
    a=n/60;
    if(a<10){
        if(b<10){
            cout<<"0"<<a<<":0"<<b;
        }
        else{
            cout<<"0"<<a<<":"<<b;
        }
    }
    else{
        if(b<10){
            cout<<a<<":0"<<b;
        }
        else{
            cout<<a<<":"<<b;
        }
    }
    return 0;
}

by lccjsw @ 2024-08-19 20:54:48

老三来了 壶关

#include<bits/stdc++.h>
using namespace std;
double s,v,m;
int n,a,t,b;
int main()
{
    cin>>s>>v;
    n=8*60+24*60;
    t=ceil(s/v)+10;
    n=n-t;
    if(n>=24*60){
        n-=24*60;
    }
    b=n%60;
    a=n/60;
    if(a<10){
        if(b<10){
            cout<<"0"<<a<<":0"<<b;
        }else{
            cout<<"0"<<a<<":"<<b;
        }
    }
    else{
        if(b<10){
            cout<<a<<":0"<<b;
        }else{
            cout<<a<<":"<<b;
        }
    }
    return 0;
}

by _Spectator_ @ 2024-08-19 20:55:24

@a20111127 你的做法可能复杂了，可以看看我的 code：

#include<bits/stdc++.h>
using namespace std;
long long s,v;
int main()
{
    cin>>s>>v;
    int t=480-ceil(s*1.0/v+10);
    if(t<0)t+=1440;
    printf("%02d:%02d",t/60,t%60);
    return 0;
}

by zhizhenyaohanyu @ 2024-08-19 20:55:45

#mnclude<bits/stdc++.h>
using namespace std;
int main(){
    double a,b,m,n,c,g;
    cin>>a>>b;
    c=ceil(a/b);
    c+=10;
    m=floor(c/60);
    n=c-m*60.0;
    if(n!=0){
        n=60-n;
        m=8-1-m;
        if(i<0){
            m=24-abs(m);
        }
    }
    if(n==0){
        m=8-m;
        if(i<0){
            m=24-abs(m);
        }
    }
    if(i>=10&&n>=10){
        cout<<m<<":"<<n<<endl;
    }
    if(i>=10&&n<10){
        cout<<m<<":"<<"0"<<n<<endl;
    }
    if(i<10&&n>=10){
        cout<<"0"<<m<<":"<<n<<endl;
    }
    if(i<10&&n<10){
        cout<<"0"<<m<<":"<<"0"<<n<<endl;
    }
    return 0;
} 

求关

by a20111127 @ 2024-08-19 22:07:18

谢谢大家