违规用户名K&xs3Z^ @ 2024-08-20 09:00:38
#include<bits/stdc++.h>
using namespace std;
queue<int> x;
queue<int> y;
char a[1110][1110];
int step=-1,n,s1,t1,s2,t2;
bool vis[1110][1110];
int fx[6]={0,0,1,0,-1};
int fy[6]={0,1,0,-1,0};
int main(){
ios::sync_with_stdio(0);
cin.tie(0);cout.tie(0);
cin>>n;
for(int i=1;i<=n;i++)for(int j=1;j<=n;j++)cin>>a[i][j];
cin>>s1>>t1>>s2>>t2;
x.push(s1),y.push(t1);
while(!x.empty()){
for(int i=1;i<=4;i++){
int tx=x.front()+fx[i];
int ty=y.front()+fy[i];
if(a[tx][ty]=='0'&&!vis[tx][ty]){
vis[tx][ty]=1;
a[tx][ty]='1';
step++;
x.push(tx),y.push(ty);
if(tx==s2&&ty==t2){
cout<<step<<endl;
return 0;
}
}
}
x.pop(),y.pop();
}
return 0;
}
by 违规用户名K&xs3Z^ @ 2024-08-20 09:01:42
@FIRESTARS gengen队 需要我们! QWQ
by FIRESTARS @ 2024-08-20 09:02:29
@违规用户名K&xs3Z^ 我来了
by Whitecrane @ 2024-08-20 09:02:46
#include<bits/stdc++.h>
using namespace std;
char a[1100][1100];
int m,n;
int sx,sy,ex,ey;
int fx[5]={0,0,1,0,-1};
int fy[5]={0,1,0,-1,0};
int q[1000300][4];
int main()
{
int h=1,t=1;
cin>>n;
for(int i=1;i<=n;i++){
for(int j=1;j<=n;j++){
cin>>a[i][j];
}
}
cin>>sx>>sy>>ex>>ey;
a[sx][sy]='1';
q[1][1]=sx;
q[1][2]=sy;
q[1][3]=0;
int tx,ty;
while(h<=t){
for(int i=1;i<=4;i++){
tx=q[h][1]+fx[i];
ty=q[h][2]+fy[i];
if(a[tx][ty]=='0'){
a[tx][ty]='1';
t++;
q[t][1]=tx;
q[t][2]=ty;
q[t][3]=q[h][3]+1;
if(tx==ex&&ty==ey){
cout<<q[t][3]<<endl;
return 0;
}
}
}
h++;
}
}
by Whitecrane @ 2024-08-20 09:03:53
用什么队列啊,数组就行
by FIRESTARS @ 2024-08-20 09:04:09
@违规用户名K&xs3Z^ 你的步数记录有问题
by FIRESTARS @ 2024-08-20 09:04:49
@违规用户名K&xs3Z^ 并不是说这是第几个被加入队列的格子这就是从起始点到他的步数
by 违规用户名K&xs3Z^ @ 2024-08-20 09:05:05
@FIRESTARS ok 窝看看
by FIRESTARS @ 2024-08-20 09:05:30
@违规用户名K&xs3Z^
hack:
3
000
000
000
1 1 3 3
by tireden @ 2024-08-20 09:05:37
楼上正解
by Deeplove_lzs @ 2024-08-20 09:05:57
https://www.luogu.com.cn/paste/b88ji1co