xu_bo_yan @ 2024-08-20 20:13:43
#include<bits/stdc++.h>
using namespace std;
long long n,w,b;
int main(){
cin>>n;
w = n/1;
b = 27+n/3+23;
if(w==b){
cout<<"All"<<endl;
}else if(w>b){
cout<<"Bike"<<endl;
}else{
cout<<"Walk"<<endl;
}
return 0;
}
by zhizhenyaohanyu @ 2024-08-20 20:14:57
@mo__li 这样
#include<bits/stdc++.h>
using namespace std;
int a;
double b,c;
int main(){
cin>>a;
b=a/1.2;
c=a/3.0+27.0+23.0;
if(c>b)
cout<<"Walk";
else if(b>c)
cout<<"Bike";
else
cout<<"All";
return 0;
}
求关qwq
by apzzzx @ 2024-08-20 20:15:46
#include<bits/stdc++.h>
using namespace std;
int n;
int main(){
cin>>n;
int a,b;
a=27+23+n/3.0;
b=n/1.2;
if(a>b){
cout<<"Walk";
}else if(a==b){
cout<<"All";
}else{
cout<<"Bike";
}
return 0;
}
by apzzzx @ 2024-08-20 20:16:18
求关
by littleFond @ 2024-08-20 20:17:27
第一,用double
第二,w=n/1.2
第三,给个关注
by lccjsw @ 2024-08-20 20:19:21
@mo__li AC:求关
#include <iostream>
using namespace std;
int main()
{
double a,b;
int n;
cin>>n;
a=(double)n/3.0+27.0+23.0;
b=(double)n/1.2;
if(a>b){
cout<<"Walk";
}else if(a<b){
cout<<"Bike";
}else{
cout<<"All";
}
return 0;
}
by Emil_ @ 2024-08-20 20:20:00
@mo__li
#include <bits/stdc++.h>
using namespace std;
int main()
{
int a;
cin>>a;
int u1=a/3.0+27+23,u2=a/1.2;
if(u1<u2)
cout<<"Bike";
else if(u1>u2)
cout<<"Walk";
else
cout<<"All";
return 0;
}
by Dejected @ 2024-08-20 20:21:02
@mo__li
来了宝贝,AC代码:求关qwq
#include<bits/stdc++.h>
using namespace std;
double b=50,c,a;
int main(){
ios::sync_with_stdio(0);
cin.tie(0);cout.tie(0);
cin>>a;
b=b+a/3;
c=a/1.2;
if(b<c){
cout<<"Bike";
}
if(c<b){
cout<<"Walk";
}
if(b==c){
cout<<"All";
}
return 0;
}
by Emil_ @ 2024-08-20 20:21:10
@mo__li
我之前没用double居然ac了
by xu_bo_yan @ 2024-08-20 20:21:48
@Emil_
by xu_bo_yan @ 2024-08-20 20:22:20
@Emil_ 谢谢