iamsharkbee @ 2024-08-22 11:22:28
#include<bits/stdc++.h>
using namespace std;
string s1,s2;
int a[10005],b[10005],c[10005];
int main()
{
cin>>s1>>s2;
int la=s1.size();
int lb=s2.size();
for(int i=1;i<=la;++i)
{
a[i]=s1[la-i]-'0';
}
for(int i=1;i<=lb;++i)
{
b[i]=s2[lb-i]-'0';
}
for(int i=1;i<=la;++i)
{
for(int j=1;j<=lb;++j)
{
c[i+j-1]+=a[i]*b[j];
c[i+j]+=c[i+j-1]/10;
c[i+j-1]%=10;
}
}
int lc=la+lb;
while(lc>0 && c[lc]==0)
{
lc--;
}
if(lc==0)
{
cout<<'0';
return 0;
}
for(int i=lc;i>=1;--i)
{
cout<<c[i];
}
return 0;
}by hexuchen @ 2024-08-22 11:23:36
@iamsharkbee 本题存在负数
by dream_dad @ 2024-08-22 11:27:53
???
by _people @ 2024-08-22 11:32:33
???
by yuhaosheng @ 2024-08-22 11:36:41
??????????????????????????????
by 陈一达2013 @ 2024-08-22 11:40:57
这道题很难吗？首先不需要用高精度算法，因为数据范围在-1e9~1e9之间，所以用int足够，只需要输出a+b就行了
by XQJ001 @ 2024-08-22 11:44:31
这道题直接用↓ int n,m; cin>>n>>m; cout<<n+m;
by ZR_HY_XS @ 2024-08-22 16:37:01
#include<bits/stdc++.h>
using namespace std;
int n,m;
int main(){
cin>>n>>m;
cout<<n+m;
return 0;
}by iamsharkbee @ 2024-08-23 08:07:06
@XQJ001
我教练要求的by iamsharkbee @ 2024-08-23 08:07:34
@hexuchen 谢谢
by iamsharkbee @ 2024-08-23 08:08:06
@hexuchen 已关