0分求助

P2626 斐波那契数列(升级版)

可以参考一下我的AC代码 ```cpp #include<bits/stdc++.h> using namespace std; long long int m,k; long long int fab(long long int n){ long long int a[100000]; a[1]=1; a[2]=1; for(long long int i=3;i<=n;i++){ a[i]=a[i-1]+a[i-2]; } return a[n]; } void fenjie(long long int j){ printf("%d=",j); for(long long int i=2;i<=j;i++){ if(j%i==0){ cout<<i; j=j/i; i=1; if(j!=1){ printf("*"); } } } } int main(){ cin>>m; k=(long long int)fab(m)%2147483648; fenjie(k); } ```
by SimonLan @ 2024-08-29 22:04:57


忘了对2^31次方取模
by SimonLan @ 2024-08-29 22:09:39


@[liyifanglan](/user/1368233)
by SimonLan @ 2024-08-29 22:10:42


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