大佬求调

houyunjie @ 2024-08-26 19:40:13

#include<bits/stdc++.h>
using namespace std;
string s1,s2;
int a[50000000],b[50000000],c[100000019];
int l;
int main(){
    cin >> s1 >> s2;
    for(int i = 0;i < s1.size();i++){
        a[s1.size () - i - 1] = s1[i] - '0';
    }
        for(int i = 0;i < s2.size();i++){
        b[s2.size () - i - 1] = s2[i] - '0';
    }
    l = s1.size();
    if(s2.size() > l){
        l = s2.size();
    }
    for(int i = 0;i < l;i++){
        c[i]=a[i] + b[i];
    }
    for(int i = 0;i < l;i++){
        if(c[i]>=10){
            c[i + 1] = c[i + 1] + c[i] / 10;
            c[i]%=10;
        }
    }
    if(c[l] != 0){
        l++;
    }
    for(int i = l - 1;i >= 0; i--){
        cout<<c[i];
    }
    return 0;
}

by 12345698pP @ 2024-08-26 20:03:11

@cff_0102 我们都知道了

by Xianzi_ @ 2024-08-26 20:05:22

P1001 不是高精度。 P1601才是高精度的 A + B Problem。

by liuhaohe @ 2024-08-27 08:59:55

@houyunjie

#include<iostream>
using namespace std;
int main()
{
    int a,b;
    cin>>a,b;
    cout<<a+b;
}

by liuhaohe @ 2024-08-27 09:00:57

@houyunjie 直接输出

by 13986586309hap @ 2024-08-27 21:30:25

#include <bits/stdc++.h>
using namespace std;

int main()
{
    int x,y;
    cin >> x >> y;
    cout << (x + y);
    return 0;
}

AC代码

by llhhss @ 2024-09-03 19:40:09

你这太复杂了看我的

#include<bits/stdc++.h>
using namespace std;
int main()
{
    int a,b;
    cin>>a>>b;
    cout<<a+b;
    return 0;
}

by MasonChong @ 2024-09-05 20:47:07

有负数，高精不行

by Soyeon @ 2024-09-10 12:44:20

@houyunjie 大袜子你...... 入门就这么卷吗